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gregori [183]
3 years ago
13

Plz answer correctly and make sure u put it in order

Chemistry
2 answers:
iren2701 [21]3 years ago
8 0

Answer: look on my page ill help you with this one but im not sure if it would be right because i dont really understand myself but look on mine

Explanation:

Aleonysh [2.5K]3 years ago
4 0

Answer:

1) Fossil Fuels

2) Burning Fossil Fuels

3) Photosynthesis

4) Plants

5) Deforestation

6) Rivers

7) Atmosphere

Explanation:

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Brenda is correct!
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The element that is in the same family as element C (gas) is likely to have which properties. 2 valence electrons, solid, metal
rewona [7]

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that element is likely to be a non metaland a gas

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2 years ago
A 25.0-ml sample of hno3 solution requires 35.7 ml of 0.108 m na2co3 to completely react with all of the hno3 in the solution. w
Rasek [7]
If we write the equation of the reaction that will take place, it is:
2HNO₃ + Na₂CO₃ → 2NaNO₃ + H₂CO3

The molar ratio of 2HNO₃ : Na₂CO₃ = 1 : 2
Therefore, we can set up the equation:
M₁V₁ = 2M₂V₂
Where the left side of the equation has the molarity and volume of HNO₃ and the right side has the molarity and concentration of Na₂CO₃. Substituting:
M₁ = (2 x 0.108 x 35.7) / 25
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5 0
3 years ago
Calculate the number of millimoles contained in 500mg of FeSO4•C2H4(NH3)2SO4.4H20 Calculate the number of grams of BaCrO4 that w
VikaD [51]

Answer:

Millimoles\ of\ FeSO_4.C_2H_4(NH_3)_2SO_4.4H_2O= 1.3084\ millimoles

The mass of BaCrO_4 required = 5.0674 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Given :

Mass = 500 mg

Molar mass of FeSO_4.C_2H_4(NH_3)_2SO_4.4H_2O = 382.1455 g/mol

Thus,

Millimoles= \frac{500\ mg}{382.1455\ g/mol}

Millimoles= 1.3084\ millimoles

Also,

Molar mass of BaCrO_4= 253.37 g/mol

Let the mass of the salt to prepare 100 mL 0.200 M solution = x g

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{253.37\ g/mol}

Moles= \frac{x}{253.37}\ mol

Given that volume = 100 mL

Also,  

1\ mL=10^{-3}\ L

So, Volume = 100 / 1000 L = 0.1 L

Molarity = 0.200 M

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

0.200=\frac{x}{253.37\times {0.1}}

x = 5.0674 g

<u>The mass of BaCrO_4 required = 5.0674 g</u>

4 0
3 years ago
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