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alisha [4.7K]
4 years ago
6

If you were to determine an objects speed what information must you have

Chemistry
1 answer:
svetoff [14.1K]4 years ago
6 0
Mass, velocity, and acceleration. :) good luck
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An electric motor produces heat while running. The amount of heat is roughly equivalent to the amount of power delivered to the motor.

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Which of the following is not an example of a molecule A. Mn     B. KOH    C. O₃    D. H₂S
goldenfox [79]

look at the chemical tables.  but i believe it is A

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Chlorine melts at 172 k what is chlorines melting point in C
Soloha48 [4]
<span><HTML><META HTTP-EQUIV="content-type" CONTENT="text/html;charset=utf-8"> <p class="answer-detail Fw-n" id="yui_3_17_2_3_1463589225479_1149"><SPAN class="ya-q-full-text" id="yui_3_17_2_3_1463589225479_1148" itemprop="text">K = 273.15 + C <BR><BR>K = 172 so substitute <BR><BR> 172 = 273.15 + C <BR><BR> C = 172 - 273.15 = -101.15</SPAN> </DIV></span>
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4 years ago
FILL IN THE BLANKWORD BANK (can use more than once): less, increases, decreases, greaterNO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)1.Disturbin
Jlenok [28]

Explanation:

If we have the following reaction at equilibrium:

<em>                                           aA + bB ⇄ cC + dD</em>

where a, b, c, and d are the stoichiometric coefficients for the reacting species A, B,  C, and D. For the reaction at a particular temperature:

                       Kc=([C]^c *[D]^d)/([A]^a *[B]^b)

where Kc is the equilibrium constant, which holds that <em>for a reversible reaction at equilibrium  and a constant temperature, a certain ratio of reactant and product concentrations has  a constant value, Kc</em> (the equilibrium constant). Note that although the concentrations  may vary, as long as the reaction in in equilibrium and temperatura don't change, the value of <u>K remains constant.</u>

For reactions that have not reached equilibrium, we obtain the reaction quotient (Qc), instead of the equilibrium  constant <u>by substituting the initial concentrations into the equilibrium constant expression.</u>

                        Qc=([Co]^c *[Do]^d)/([Ao]^a *[Bo]^b)

To determine the direction in wich the net reaction will proceed to reach equilibrium, que compare the values of Qc and Kc.

  • Qc < Kc: To reach equilibrium, reactants must be converted to products (→)
  • Qc = Kc: The initial concentrations are equilibrium concentrations. The system in at equilibrium.
  • Qc > Kc: To reach equilibrium, products must be converted to reactants (←)

Solution:

We have the following reaction:

                             NO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)

So:

Kc=([NOCl]^1*[NO2]^1)/([NO2Cl]^1 *[NO]^1)

     =([NOCl][NO2])/([NO2Cl][NO])  

1. In the equation above, [NO2Cl] it's in the denominator, so if we increase it's numericall value by adding NO2Cl <u>decreases Qc  to a value less than Kc.</u>

<em>(From the chemical point of view, if we disturb the equilibrium adding NO2Cl (a reactant), to reach equilibrium again the system proceeds from left to right (→) consuming this reactant.)</em>

2. To reach a new state of equilibrium (<em>where Qc = Kc</em>), Qc therefore  increases wich means that the denominator of the expression for Qc  decreases <em>(in order to increase the denominator as mention above).</em>

3. To accomplish this, the concentration of reageants decreases <em>(reagents are being consumed), </em>and the concentration of prodcuts increases <em>(products are being formed).</em>

4 0
3 years ago
Energy and Temperature Activity Worksheet
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Answer:

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Explanation:

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