Look dj. Hi can do that is your answer
If you have studied enzymes its a similar concept. Cells have proteins on the surface of their cell which hormones bind to (called receptors) The receptor must be a complimentary shape to the hormone for it to bind. Only target cells have the receptor with the complimentary shape so only these cells will be affected.
Answer:
-1605.1 kJ
Explanation:
The enthalpy of formation is the enthalpy of the reaction that forms the substance only by its constituents, so, substances formed by one element, such as O2, in its ambient temperature phase, have an enthalpy of formation 0.
The enthalpy is a measure of how much heat the system contains, and so, the variation of it measures the heat lost (ΔH <0) or gained (ΔH >0), and for a reaction:
ΔHrxn = ∑ni*ΔHi products - ∑ni*Hi reactants
Where ni represents the coefficient of the substance, so by the data given:
ΔHrxn = [2*(-241.82) + (-393.5)] - [-74.6]
ΔHrxn = -802.54 kJ/ mol of CH4
Thus, the heat released is the enthalpy multiplied by the number of moles of CH4:
Q = -802.54*2
Q = -1605.1 kJ
Answer:
![2Al+6HCl\rightarrow 2AlCl_3+3H_2](https://tex.z-dn.net/?f=2Al%2B6HCl%5Crightarrow%202AlCl_3%2B3H_2)
5.39 g
Explanation:
The balanced equation for the reaction of aluminum with hydrochloric acid is shown below as:-
![2Al+6HCl\rightarrow 2AlCl_3+3H_2](https://tex.z-dn.net/?f=2Al%2B6HCl%5Crightarrow%202AlCl_3%2B3H_2)
Given,
Pressure = 0.750 atm
Temperature = 30.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (30.0 + 273.15) K = 303.15 K
T = 303.15 K
Volume = 10.0 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.750 atm × 10.0 L = n × 0.0821 L.atm/K.mol × 303.15 K
⇒n = 0.3013 moles
Moles of hydrogen obtained = 0.3013 moles
From the reaction,
3 moles of hydrogen gas are furnished when 2 moles of aluminum is consumed.
Also,
1 mole of hydrogen gas are furnished when
mole of aluminum is consumed.
Thus,
0.3013 mole of hydrogen gas are furnished when
mole of aluminum is consumed.
Moles of aluminum consumed = 0.2 moles
Also, Molar mass of aluminum = 26.981539 g/mol
So, Mass = Moles*Molar mass = 0.2 moles*26.981539 g/mol = 5.39 g
Answer:
A. The reaction will proceed forward forming more CH4
B. The reaction will proceed forward forming more CH4
C. Since the reaction is exothermic, raising the temperature will cause the reaction to proceed backward, thus forming C and H2.
D. Lowering the volume makes the gas particles to be more close together thereby enhancing their collisions leading to reaction. Therefore the reaction will proceed forward forming more CH4
E. Catalyst only reduce the activation energy so the reaction can proceed faster. The reaction will proceed forward forming.
F. The following will favour CH4 at equilibrium
i. Catalyst to the reaction mixture,
ii. Both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture
iii. Adding more C to the reaction mixture.