Answer: Option (4) is the correct answer.
Explanation:
It is known that equilibrium constant is represented as follows for any general reaction.

K = ![\frac{[C][D]}{[A][B]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BC%5D%5BD%5D%7D%7B%5BA%5D%5BB%5D%7D)
As equilibrium constant is directly proportional to the concentration of products so more is the value of equilibrium constant more will be the number of products formed.
As a result, more is the time taken by the reaction to reach towards equilibrium. Whereas smaller is the value of equilibrium constant more rapidly it will reach towards the equilibrium.
Thus, we can conclude that cases where K is a very small number will require the LEAST time to arrive at equilibrium.
ADD THEM all, and then divide by four. Thats what I would do!
I believe this answer is A. Moving electrons generate magnetic forces. Hope this helps!!! :)
Radioactive material undergoes 1st order decay kinetics.
For 1st order decay, half life = 0.693/k
where k = rate constant
k = 0.693/half life = 0.693/8.02 = 0.0864 day-1
Now, for 1st order reaction,
k =

Given: t = 6.01d, initial conc. = 5mg
∴0.0864 =

∴ final conc. = 2.975 mg