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satela [25.4K]
4 years ago
10

An electrolytic cell Group of answer choices consumes electrical current to drive a nonspontaneous chemical reaction. produces e

lectrical current from electricity. produces electrical current from a nonspontaneous chemical reaction. produces electrical current from a spontaneous chemical reaction. consumes electrical current to drive a spontaneous chemical reaction
Chemistry
1 answer:
Rzqust [24]4 years ago
3 0

Answer:

produces electrical current from electricity. produces electrical current from a nonspontaneous chemical reaction.

Explanation:

An electrolytic cell converts electrical energy into chemical energy. Here, the redox reaction is spontaneous and is responsible for the production of electrical energy. The reaction at the anode is oxidation and that at the cathode is reduction. Here, the anode is positive and the cathode is the negative electrode.

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It is difficult to press the football in water why?​
Sati [7]

Answer:

The ball you want to submerge displaces the water occupied in the ball's volume. ... In water the concrete has a buoyancy pressure force equal to the displaced liquid's weight and weighs only 120 pounds until it reaches the surface.

Explanation:

8 0
3 years ago
A compound sample contains 60.87% c, 4.38% h, and 34.75% o by mass. it has a molar mass of 276.2 g/mol. what are the empirical a
Allushta [10]

Step 1) Assume we have 100 grams of the compound. Thus, we're starting with 60.87 grams C, 4.38 grams H, and 34.75 grams O.

Step 2) Convert the masses of each to moles.

60.87 grams C=5.068276436 mol C

4.38 grams H=4.345238095 mol H

34.75 grams O=2.171875 mol O

step 3) Determine your simplest whole-number ratio of moles by dividing each number of moles by the smallest number of moles. (In this case, the smallest number of moles is 2.171875 mol O)

O: \frac{2.171875}{2.171875} = 1

H:\frac{4.345238095}{2.171875} = 2

C: \frac{5.068276436}{2.171875} = 2.33

Step 4) Whenever you're doing an empirical formula problem, and you run into a number that ends with .33, rather than rounding down to a whole number, you need to multiply all your ratios by 3 to obtain whole numbers. Thus, you will get:

O=3

H=6

C=7

Step 5) write the empirical formula using the ratios.

The empirical formula is: C₇H₆O₃

Step 6) The subscripts in the molecular formula of a substance are always whole-number multiples of the subscripts in its empirical formula. This multiple is found by dividing the molecular weight (which was given to us in the problem: 276.2 amu) by the empirical formula weight (C₇H₆O₃ =138.118 amu).

\frac{276.2}{138.118} = 2

Step 7) simply multiply the subscripts in the empirical formula by the multiple, 2, and you will get the molecular formula.

The molecular formula is: C₁₄H₁₂O₆

6 0
3 years ago
By what factor will the rate of the reaction change if the ph decreases from 6.00 to 2.00? express your answer numerically using
jeyben [28]
The reaction equation is first order with respect to [H+]

when PH1 = -㏒[H+]1  so, when PH = 6

So by substitution:

∴ 6 = -㏒[H+]1

∴[H+]1 = 1 x 10^-6

and when PH2 = -㏒[H+]2 so, when PH2 = 2

so by substitution:

∴ 2 = -㏒[H]2

∴[H]2 = 1 x 10^-2

So the rate of reaction changes by the factor of:

[H2]2/[H]1 = (1 x 10^-2) / (1 x 10^-6) = 10000

It is 10000 times faster when PH decreases from 6 to 2
5 0
4 years ago
The movement of broken down pieces of rock from one place to another is called
Dvinal [7]

Answer:

The answer I believe is B. Erosion

Explanation:

Just sounds better than all the other choices.

7 0
3 years ago
Read 2 more answers
Two identical bottles at the same temperature contain the same gas. If bottle B has twice the volume and contains half the numbe
yuradex [85]

Answer:

The ratio of pressure in bottle B to that of bottle A is 1 : 4

Explanation:

We'll be by calculating the pressure in both bottles. This is illustrated below below:

For A:

Temperature (T) = T

Volume (V) = V

Number of mole (n) = n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

PV = n x 0.0821 x T

Divide both side by V

P = nT0.0821/V

Therefore, the pressure, in bottle A is

PA = nT0.0821/V

For B:

Temperature (T) = the same as that of A = T

Volume (V) = twice that of A = 2V

Number of mole (n) = half that of A = ½n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

P x 2V = ½n x 0.0821 x T

Divide both side by 2V

P = ½n x 0.0821 x T/2V

P = nT0.0821/4V

Therefore, the pressure in bottle B is:

PB = nT0.0821/4V

Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:

Pressure in bottle A (PA) = nT0.0821/V

Pressure in bottle B (PB) = nT0.0821/4V

PB/PA = nT0.0821/4V ÷ nT0.0821/V

PB/PA = nT0.0821/4V x V/nT0.0821

PB/PA = 1/4

Therefore, the ratio of pressure in bottle B to that of bottle A is 1 : 4.

3 0
3 years ago
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