Answer:
a) The theoretical yield is 408.45g of 
b) Percent yield = 
Explanation:
1. First determine the numer of moles of
and
.
Molarity is expressed as:
M=
- For the 
M=
Therefore there are 1.75 moles of 
- For the 
M=
}{1Lsolution}[/tex]
Therefore there are 2.0 moles of 
2. Write the balanced chemical equation for the synthesis of the barium white pigment,
:

3. Determine the limiting reagent.
To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:
- For the
:

- For the
:

As the
is the smalles quantity, this is the limiting reagent.
4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:
Percent yield = 
Percent yield = 
The real yield is the quantity of barium white pigment you obtained in the laboratory.
It’s true:)
The subscript on chemical equations tells you how many atoms the elements have. If there is no subscript then there is only 1 atom.
Explanation:
The second quantum number also called the orbital quantum number describes the type of orbital or shape of it.
Answer: D. The specific orbital within a sublevel.
Hey there!
Sulfuric acid: H₂SO₄
H: 2 x 1.008 = 2.016
S: 1 x 32.065 = 32.065
O: 4 x 16 = 64
--------------------------------
98.081 g/mol
The molar mass of sulfuric acid is 98.081 g/mol.
Hope this helps!