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avanturin [10]
2 years ago
15

1 Shannon runs at a constant rate. She can run 3 miles in 26 minutes. What distance, Y in miles, can she run in 15 minutes, x?

Mathematics
1 answer:
Crazy boy [7]2 years ago
7 0

Answer:

1,75 miles

Step-by-step explanation:

3 miles ______26 minutes

1 miles =>26 :3 =8,5 (8 minutes and 5 seconds)

15:8,5 =1,75 miles

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2x+8y = 6<br> 15x + 20y = 15
Likurg_2 [28]

Answer:

The solution is (0, 3/4)

Step-by-step explanation:

Please copy and share the instructions.  Here they are:  Solve the following system of linear equations.

Both of the equations can be reduced (simplified):

2x+8y = 6            =>  x + 4y = 3

15x + 20y = 15     => 3x + 4y = 3

Let's use the elimination by addition and subtraction method.  Multiply the first equation by -1, obtaining

                                 -x - 4y = -3

Add the second       3x + 4y = 3

equation to the

first.

We get:                       2x = 0.

Thus, x = 0.  Substituting 0 for x in the 1st original equation yields:

2(0) + 8y = 6.  Then y = 6/8, or y = 3/4.

The solution is (0, 3/4).

4 0
3 years ago
Both Andrew and Karleigh recorded the distance they ran in x minutes on treadmills. Andrew A 2-column table with 2 rows. Column
mars1129 [50]

Answer:

ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.

That is, S = D/t

Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have

S1 = D1/t

We can then say he ran a distance

D1 = t × S1

= 3600S1

Similarly, let's say Karleigh ran a distance

D2 = t × S2

= 3600S2

Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.

Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10

D1 = 3600 × 5

= 18000

D2 = 3600 × 10

= 36000

This makes D2 bigger than D1. this is an example i found on the internet.

Step-by-

hope this helps, good luck

7 0
3 years ago
Read 2 more answers
Show work please!...
Leni [432]

Answer:what goes around comes around

Step-by-step explanation:

"i need points too thanks"

7 0
2 years ago
Use long division to find the quotient. <br><br>(x²+6x-27) ÷ (x-3)
Alex
\frac{ x^2+6x-27 }{x-3} = \frac{ x^2+6x +3x-3x-27 }{x-3} = \frac{ x^2+9x-3x-27 }{x-3} = \\ \\ =\frac{ x(x +9 )-3(x+9) }{x-3} = \frac{ (x +9 ) (x-3) }{x-3} = x+9 \\ \\ \\ x-3\neq 0 \\x\neq 3\\D=R\setminus \left \{ 3 \right \}


4 0
2 years ago
Determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give an example tha
ioda
True.

You're allowed to move stuff around. Dogs of the AMS.

y' = 3y - 2x + 6xy - 1 \\&#10;y' = 3y + 6xy - 2x - 1 \\&#10;dy/dx= 3y(1 + 2x) - (2x + 1) \\&#10;dy/dx = 3y(1 + 2x) - (1 + 2x) \\&#10;\frac{dy}{dx} = (3y - 1)(1 + 2x) \ \Rightarrow\ \dfrac{dy}{3y-1} = (1 + 2x) dx

We wrote it in the form dy/dx = g(x) f(y) so this is separable.
3 0
2 years ago
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