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2 years ago

Hello can anyone give me the full answer to this step by step?

Mathematics

2 answers:

Andre45 [30]2 years ago

5 0

Answer:

1. f = 16 degrees

2. h = 10 degrees

Step-by-step explanation:

1. f = (180 - 67+46 - 4) / 4

2. h = (180 - 60 + 90) / 3

OLga [1]2 years ago

5 0

Answer:

f=16

h=10

Step-by-step explanation:

4f+3+46+67=180

180-(3+67+46)=64

64/4=16

f=16

h=10

60+90+3h=180

h= 10

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using the graphing method to solve the equation 13(0.25)^x=7 Round your answer to the nearest thousandth

netineya [11]

Answer:

x = 0.447

Step-by-step explanation:

You need to use your graphing calculator for this.

In y=, put 13(0.25)^x in Y1 and put 7 in y2. Using 2nd trace, find the intersections.

The answer I got was x = 0.447.

3 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$