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notsponge [240]
3 years ago
7

How could sinking a ship to create an artificial reef address the problem?

Chemistry
1 answer:
Ray Of Light [21]3 years ago
7 0

Answer:

C.  There would be more places for new species to enter the ecosystem.

Explanation:

The Shipwrecks established artificial reefs that address the problem of a natural reef.

The artificial reefs provide a stable growing area for corals, and habitat for fishes and new organisms along with food sources that is found in natural reefs. This helps to increase the growth of marine life.

Hence, the correct answer is "C.  There would be more places for new species to enter the ecosystem."

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What metal has the highest melting point and what is it used for?
irina1246 [14]
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3 years ago
What is the purpose of an ionic bond?
Yuri [45]

Answer:

Ionic bonds are important because they allow the synthesis of specific organic compounds. Scientists can manipulate ionic properties and these interactions in order to form desired products. Covalent bonds are especially important since most carbon molecules interact primarily through covalent bonding

Explanation:

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4 0
3 years ago
Aqueous solutions of silver nitrate (agno3) and iron (iii) chloride (fecl3) are mixed together. which ion combines with the chlo
zaharov [31]
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4 0
4 years ago
Read 2 more answers
What is the predicted ionic charge of an element in group via/16?
Serga [27]

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8 0
4 years ago
How many atoms are there in 0.32g of copper
aivan3 [116]

The number   of atoms that are in 0.32 g  of  copper  are

 3.01 x10^21  atoms


        <u><em>calculation</em></u>

<u><em>    </em></u>Step  1: find the number of moles  of Copper

       moles =  mass/molar  mass

      =  0.32  g /63.5  g/mol=0.005  moles

 Step  2:  use the Avogadro's  constant  to determine  the  number of  atom                

             in  0.005 moles of Cu

 that is   according to  Avogadro's  law   1 mole =6.02 x10^23 atoms

                                                                    0.005 moles=?  atoms

          by cross   multiplication

  =  (0.005  moles  x 6.02 x10^23 atoms) /  1 mole= 3.01 x10 ^21 atoms


7 0
3 years ago
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