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leonid [27]
3 years ago
15

The moon Phobos orbits Mars

Physics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

The moon Phobos orbits Mars (m = 6.42 x 1023 kg) at a distance of 9.38 x 106 m.

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An object is dropped from rest from a height 5.6 × 106 m above the surface of the earth. If there is no air resistance, what is
marshall27 [118]

Answer:

The answer to your question is:  10.48 km/s

Explanation:

Data

h = 5.6 x 10⁶ m

g = 9.8 m/s²

Formula

                 vf = \sqrt{2gh}

Substitution

                vf = \sqrt{2(5.6 x 10^{6}) (9.81)}

                vf = \sqrt{109760000}

                vf = 10476.64 m/s

convert to km/s

               vf = 10476.64/1000

               vf = 10.48 km/s

6 0
3 years ago
If you go to the beach on a hot summer day, the temperature of the sand is much higher than the temperature of the water. If we
guapka [62]
Water has a higher specific heat so it requires more energy to heat than sand.
7 0
3 years ago
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Carter pushes a bag full of basketball jerseys across the gym floor. The he pushes with a constant force of 21 newtons. If he pu
myrzilka [38]
Power is the rate of work that is done per time. Work is calculated from the product of force and the displacement. So, by using the definition of power and work, we can relate power with force, displacement and the time. We do as follows:

Power = Work / time
Power = Force x displacement / time
Power = 21 N (9 m) / 3 s
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6 0
3 years ago
a hunter 412.5m from a cliff moves a distance x towards the cliff and fires a gun. he hears the echo from the cliff after 2.2sec
Inessa [10]

Answer: 49.5 m

Explanation:

The speed of sound s is given by a relation between the distance d and the time t:

s=\frac{d}{t} (1)

Where:

s=330 m/s is the speed of sound in air (taking into account this value may vary according to the medium the sound wave travels)

d=412.5 m-x since we are told th hunter was initially 412.5 meters from the cliff and then moves a distance x towards the cliff

t=\frac{2.2 s}{2}=1.1 s Since the time given as data (2.2 s) is the time it takes to the sound wave to travel from the hunter's gun and then go back to the position where the hunter is after being reflected by the cliff

Having this information clarified, let's isolate d and then find x:

d=st (2)

412.5 m-x=(330 m/s)(1.1 s) (3)

Finding x:

x=49.5 m This is the distance at which the hunter is from the cliff.

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