The answer is easy if you know the physics.
<span>a/a' = (r/R)^2 = (r/9r)^2 = 1/81; so that a = a'/81.
A's radial acceleration must be 1/81 of B's. And each acceleration is a = v^2/R and a' = V^2/r, where v and V are the tangential speeds you want the ratio for. </span>
<span>a = v^2/R = v^2/9r = V^2/81r = a'/81 In which case v^2/V^2 = 9/81 = 1/9; so that 1/3 = Va/Vb ANS</span>
Answer:
the speed of the satellite is 12,880.53 km/h
Explanation:
Given;
radius of the circular orbit, r = 24,600 km
time taken to revolve around Earth, t = 12 hours
The circumference of the satellite is calculated as;
L = 2πr
L = 2π x 24,600 km
L = 49,200π km
L = 154,566.36 km
The speed of the satellite;
v = L/t
v = 154,566.36 / 12
v = 12,880.53 km/h
Therefore, the speed of the satellite is 12,880.53 km/h
Answer:
252J
Explanation:
Given parameters:
Distance = 72m
Force = 3.5N
Unknown:
Work done on the house = ?
Solution:
Work done is the force applied to move a body through a particular distance.
Work done = Force x distance
Now insert the parameters and solve;
Work done = 3.5 x 72 = 252J
The formula for average speed is,
S= Total Distance Covered / Total Time Taken
In the given problem,
The total distance covered is 162 miles.
Since only the times are given, we have to determine how many hours did the car traveled from 7:30am to 10:30am.
To get the number of hours: First, subtract the hours, then the minutes. Hours: 10-7=3
Minutes: 30-30=0
Therefore,
S = 162miles/3hrs
S = 54miles/hr
The average speed of the car is 54miles/hr.
Strength: able to detect planets in a wide range of orbits, as long as orbits aren't face on
Limitations: yield only planet's mass and orbital properties
