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Potential difference required in an electron microscope to give an electron wavelength of 4. 5 nm will be 0.063 V.
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other is called potential difference.
The wavelength of an electron is calculated for a given energy (accelerating voltage) by using the de Broglie relation between the momentum p and the wavelength λ of an electron
lambda = 4.5 nm = 4.5 * m
h = J s
e = 1.6 * C
m = 9.1 * kg
Energy = eV
lambda = h / = h /
=
/ (2m (eV))
V = / (2 m e
)
V = / 2 * 9.1 *
* 1.6 *
*
V = 0.063 V
To learn more about wavelength of an electron here
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