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12345 [234]
3 years ago
10

An amusement park charges a $15 entrance free plus $3.25 for each ride. Part A: Write an equation that represents the situation.

Write your answer in the box. Part B: Identify the initial value and the rate of change for the function that represents the situation. Part C: How much would it cost to enter the amusement park and ride on seven rides? Show your work.
Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

Look below

Step-by-step explanation:

Part A: Equation would be in the y=mx+b format. m, or the slope, would be the cost that varies depending on the number of things that happen so m=3.25. b would be the fix cost so it is 15 so the equation ends up being y=$3.25x + $15.

Part B: Initial value is 15 since it is the fix cost, and 3.25 is the rate of change since it added as the number of rides increase.

Part 3: To solve this you substitute 7 into x so y=$3.25(7) + $15 = $37.75

I hope this explains it well.

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The 100th term of ​ 70, 100, 130
fgiga [73]

Answer:

3040

Step-by-step explanation:

given arithmetic progression is

70,100,130,...

here

first term (a)=70

common difference (d)=100-70=30

number of term n=100

using the formula of arithmetic progression

an=a+(n-1)d

a100=70+(100-1)30

a100=70+99×30

a100=70+2970

a100=3040

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2 years ago
X+4y=4 in slope intercept form
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Answer:

Slope: −14y-intercept: (0,1)

Step-by-step explanation:

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3 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

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A picture frame is shaped like a rectangle whose perimeter is 196 cm. The length is 6 times long as the width
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L=length W=width
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Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same

196=2(6W)+2W
196=12W+2W
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W=14cm
L= (14x6) 84cm
3 0
3 years ago
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