Answer:
3040
Step-by-step explanation:
given arithmetic progression is
70,100,130,...
here
first term (a)=70
common difference (d)=100-70=30
number of term n=100
using the formula of arithmetic progression
an=a+(n-1)d
a100=70+(100-1)30
a100=70+99×30
a100=70+2970
a100=3040
Answer:
Slope: −14y-intercept: (0,1)
Step-by-step explanation:
Answer:
740
Step-by-step explanation:
The n th term of an arithmetic series is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then
a₁ + 2d = 7 → (1)
a₁ + 6d = 23 → (2)
Subtract (1) from (2) term by term
4d = 16 ( divide both sides by 4 )
d = 4
Substitute d = 4 into (1)
a₁ + 2(4) = 7
a₁ + 8 = 7 ( subtract 8 from both sides )
a₁ = - 1
The sum to n terms of an arithmetic series is
=
[ 2a₁ + (n - 1)d ] , thus
=
[ (2 × - 1) + (19 × 4) ]
= 10(- 2 + 76) = 10 × 74 = 740
L=length W=width
perimeter=2Lx2W
196=2L+2W
Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same
196=2(6W)+2W
196=12W+2W
196=14W
W=14cm
L= (14x6) 84cm