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Kamila [148]
2 years ago
11

What is the mass of one mole of hydrogen molecules?

Chemistry
2 answers:
liberstina [14]2 years ago
5 0
2 grams exactly❤️ hope this helps
Lilit [14]2 years ago
4 0

Answer:

2 grams

Explanation:

One MOLE of hydrogen atoms contains the same number of atoms as the number of hydrogen molecules in one MOLE of hydrogen molecules, i.e., Avagadros number. However, one mole of hydrogen atoms has a mass of 1 gram while one MOLE of hydrogen molecules has a mass of 2 grams.

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How are biology and Chemistry are related give any two points or reasons​
k0ka [10]

Answer:

Both of them are related most of the structures of human body .The working of cells, the cellular respiration processes ,the proteins synthesizing carbohydrates syntheses lipids synthesis and many other reactions involves chemistry.

•Chemistry and biology both are branches of science so they are much more related to each other.

Explanation:

<h2>I hope it's helpful for you</h2>
6 0
2 years ago
Read 2 more answers
Like Earth, the moon
dedylja [7]
Um all? i’m confused
5 0
2 years ago
If you could help me that would be awesome
elixir [45]
There are 3 significant figures. Significant numbers are the numbers that build up your total number. 1-9 always count, 0 only counts if it’s after another number. For example: 0,901 has 3 significant numbers as does 0,910. 9,10 also has 3. 0,09 has just 1.
8 0
3 years ago
You’ve just started a new job in the laboratory of the Food and Drug Administration. Your supervisor asks you to prepare a 1.50-
anastassius [24]

Answer:  118.5 grams

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml = 500 ml

1.50=\frac{moles\times 1000}{500ml}

moles = 0.75

moles of solute =\frac{\text {given mass}}{\text {molar mass}}

0.75 =\frac{\text {given mass}}{158g/mol}

mass of KMnO_4 = 118.5 grams

Thus mass of KMnO_4 needed to prepare 500 mL of this solution iis 118.5 grams

6 0
2 years ago
Compare the volume of 14.1 g of helium to 14.1 g of argon gas (under identical conditions).
s2008m [1.1K]
The Volumes can be calculated from Masses by using following Formula,

                                        Density  =  Mass / Volume
Solving for Volume,
                                        Volume  =  Mass / Density

Mass of Both Gases  =  14.1 g

Density of Argon at S.T.P  =  1.784 g/L

Density of Helium at S.T.P  =  0.179 g/L

For Argon:
                                        Volume  =  14.1 g / 1.784 g/L

                                        Volume  =  7.90 L

For Helium:
                                        Volume  =  14.1 g / 0.179 g/L

                                        Volume  =  78.77 L
4 0
3 years ago
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