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2 years ago

PLEASE HELP ASAP! AND PLEASE DO NOT GIVE ME ANY VIRUSES!

Chemistry

1 answer:

sertanlavr [38]2 years ago

8 0

Answer:

The first one and the last one.

Explanation:

Carbon dioxide is generated by cellular respiration and released into the atmosphere.

Photosynthesis makes oxygen that plants can release into the atmosphere.

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An aluminum can weighing 10 g absorbs 106.8 J of heat and warms by 12 degrees C. What is the specific heat of the aluminum can?

Sladkaya [172]

Answer:

$c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}$

Explanation:

The heating process is modelled after the First Law of Thermodynamics:

$Q = m \cdot c_{Al}\cdot \Delta T$

The specific heat of the aluminium can is:

$c_{Al} = \frac{Q}{m\cdot \Delta T}$

$c_{Al} = \frac{106.8\,J}{(10\,g)\cdot (12^{\circ}C)}$

$c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}$

8 0

3 years ago

When water is solid, do molecules move?

BabaBlast [244]

Answer:

Ice is water in its solid form. Ice keeps its shape, even if it's removed from the container. The molecules in ice are locked into place and cannot move or slide past one another, but they do vibrate a little bit.

Explanation:

As the temperature drops or decreases, the water molecules gradually slow down. Eventually they stop moving and simply vibrate back and forth. At this point ice is formed, the solid phase of water. If the temperature is allowed to increase, the molecules will once again begin to vibrate faster and faster.

8 0

2 years ago

Read 2 more answers

If 6.89 g of CuNO3 is dissolved in water to make a 0.460 M solution, what is the volume of the solution?

Readme [11.4K]

3.67 grams is the volume of the solution

6 0

3 years ago

10. Write the formula for the compounds: copper (1) chloride and copper (II) chloride

Natali [406]

Answer:

Copper(II) chloride (CuCl2) reacts with several metals to produce copper metal or copper(I) chloride (CuCl) with oxidation of the other metal.

Explanation:

3 0

2 years ago

What is the oh- in a solution with a poh of 5.71

Rudik [331]

Answer:- The hydroxide ion concentration of the solution is $1.95*10^-^6$ .

Solution:- The formula used to calculate pOH from hydroxide ion is:

$pOH=-log[OH^-]$

When pOH is given and we are asked to calculate hydroxide ion concentration then we multiply both sides by negative sign and take antilog and what we get on doing this is:

$[OH^-]=10^-^p^O^H$

pOH is given as 5.71 and we are asked to calculate hydrogen ion concentration. Let's plug in the given value in the formula:

$[OH^-]=10^-^5^.^7^1$

$[OH^-]$ = 0.00000195 or $1.95*10^-^6$

So, the hydroxide ion concentration of the solution is $1.95*10^-^6$ .

3 0

3 years ago