Find the missing side lengths. Leave your answer as radicals in simplest form.

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = <u><em>sample mean diameter</em></u>

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)

= 1 - 0.6406 = <u>0.3594</u>

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

8 0

3 years ago

Have you ever been swimming in a pool, and your eyes were red when you get out this means the chemicals in the pool were not adj

kherson [118]

I like your words, Mr. Magicman

8 0

2 years ago

I need help with this problem if anyone can help ASAP please help !

MakcuM [25]

Answer:

42

Step-by-step explanation:

7 0

3 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary).

Evgesh-ka [11]

Answer:

approximately 8.5

Step-by-step explanation:

So you can use the distance formula: $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\$ which is derived from the Pythagorean theorem because normally x2-x1 would kind of give the distance length between x2 and x1 except sometimes it would be negative which wouldn't make much sense right? but it doesn't matter because it's being squared so the value ultimately becomes positive, and the same thing goes for the y-value. the distance between x2 - x1 really represents the base and y2-y1 represents the height and then adding them together gives the hypotenuse squared which is why you take the square root over the entire thing to find the distance, since the hypotenuse is the shortest distance between two points

Now all you have to do is plug the values in to get

$\sqrt{(-7 - (-4))^2 + (-8 - 0)^2}\\\sqrt{(-3)^2 + (-8)^2}\\\sqrt{9 + 64}\\\sqrt{73}\\distance \approx 8.5$

5 0

2 years ago

Dentro de 11 años, la edad de Federico será la mitad del cuadrado de la que tenía hace 13 años. Calcula la edad de Federico.

Bad White [126]

Plantearemos una ecuación cuadratica, y resolviendola veremos que Federico tiene 21 años.

<h3>¿Como plantear la ecuación que debemos resolver?</h3>

Lo primero que debemos hacer es definir la variable que vamos a usar, en este caso usare:

F = edad de Federico.

Dentro de 11 años, la edad de Federico será:

F + 11

Hace 13 años, la edad de Federico era:

F - 13

Reemplazando eso en lo que el problema plantea, tenemos:

(F + 11) = 0.5*(F - 13)^2

Ahora podemos resolver esto para F.

F + 11 = 0.5*(F^2 - 26*F +169)

F + 11 = 0.5*F^2 - 13*F + 84.5

Movemos todo al mismo lado:

F + 11 - 0.5*F^2 + 13*F - 84.5 = 0

-0.5*F^2 + 14*F - 73.5 = 0

Ahora tenemos una ecuación cuadratica, la cual resolvemos usando la formula de Bhaskara:

$F = \frac{-14 \pm \sqrt{(14)^2 - 4*(-0.5)*(-73.5)} }{2*(-0.5)} =\frac{-14 \pm 7}{-1}$

Esto nos da dos valores:

F = (-14 + 7)/-1 = 7
F = (-14 - 7)/-1 = 21

El problema con el primer valor, es que es inconsistente con el enunciado, ya que en ese caso, Federico hace 13 años tendría una edad negativa. Así que <u>descartamos la primer solución</u> y nos quedamos con la segunda.

F = 21

Federico tiene 21 años.

Sí quieres aprender más sobre ecuaciones cuadraticas, puedes leer:

brainly.com/question/17102578

7 0

2 years ago