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KonstantinChe [14]

3 years ago

5

The difference of three times Faye's age and four times Joshua's age is 31. If Faye's age is five more than twice Joshua's age,

how old is Faye?

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

She is 31

F-Faye
J-Joshua

F3-J4=31
F=J2+5
(J2+5)(3)-J4=31
J2+5=31
J2+5-5=31-5
J2=26
J2/2=26/2
J=13

F=13(2)+5
F=26+5
F=31

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