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Paul [167]
3 years ago
9

Do you need need water? Lol(This is just so you can get some points)​

Health
2 answers:
alexandr1967 [171]3 years ago
8 0
I’m thirsty lollolol
elena55 [62]3 years ago
4 0

Answer:

yes

Explanation:

hi

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eth is 18 years old, weighs 250 pounds, and is 72 inches tall. Use the formula and chart below to evaluate his weight, and then
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Seth's body mass index amounts to 33.9. He is classified as obese.


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Seth's BMI indicates the letter A. He has a slight risk of weight-related diseases.


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Which of the following would not be considered a foul
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See explanation?

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What options are there

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Jack runs a company and is constantly under pressure. When he went to the doctor recently, he was advised to engage in aerobic e
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C. Hypertension

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If you were to try and pair a thymine with a cytosine (a non Watson-Crick base pairing), then would you expect to see any stabil
jeyben [28]

Answer:

D. Yes, two hydrogen bonds could form between thymine and cytosine.

Explanation:

A hydrogen bond (often informally abbreviated H -bond) is a primarily electrostatic force of attraction between a hydrogen (H) atom which is covalently bound to a more electronegative atom or group, particularly the second-row elements nitrogen (N), oxygen (O), or fluorine (F)—the hydrogen bond donor (Dn)—and another electronegative atom bearing a lone pair of electrons—the hydrogen bond acceptor (Ac).

The formation of stable hydrogen bonds depends on the distance between two strands, the size of the bases and geometry of each base. Stable pairings occur between guanine and cytosine and between adenine and thymine (or adenine and uracil in RNA).

One hydrogen bond could form between the C4 carbonyl group on thymine (a hydrogen bond acceptor) and the C4 amino group on cytosine (a hydrogen bond donor). Another hydrogen bond could form between N3 of thymine (a hydrogen bond donor) and the N3 of cytosine (a hydrogen bond acceptor). Note that the C2 carbonyl groups found on both bases are both hydrogen bond acceptors and therefore a hydrogen bond cannot be formed between them.

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