The theory of endosymbiosis suggests that a<span> primitive aerobic prokaryote was engulfed by a larger anaerobic prokaryote. C
HOPE THIS HELPS! ^_^</span>
Answer:
A. Yes, because the %A approximately equals the %T and the %G approximately equals the %C in both species.
Explanation:
According to Chargaff's rule, in all cellular DNAs, the number of adenosine residues (A) is equal to the number of thymidine residues (T). And the number of guanosine residues (G) is equal to the number of cytidine residues (C). Therefore, the sum of the purine residues equals the sum of the pyrimidine residues (A+ G= C+ T). It is based on the fact that a purine base always pairs with a pyrimidine base in a double helix DNA.
Chargaff’s rule is followed in all the double-helical DNA molecules irrespective of the species. In DNAs of sea urchin and salmon, the percentage of adenine is equal to that of the thymine and the percentage of guanine is equal to that of the cytosine. Therefore, Chargaff's rule is followed.
B - Only the Neutrons are involved in the fission reaction
They're called Enzyme. They're made up of proteins. They act as a biological catalysts that can speed up chemical reaction. They have an active site that certain substrates binds into it and form a product. Enzyme works under optimum pH and temperature and the active sites are not changed unless denatured.
I’m not sure but I think it’s A or C
