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Tasya [4]
2 years ago
12

Allison stands 180 meters away from a steep canyon wall. She shouts and hears the echo of her voice one second later. What is th

e speed of the wave?
Physics
1 answer:
ratelena [41]2 years ago
3 0

Answer:

V = S / t     speed of wave

V = 2 * 180 m / 1 sec = 360 m/s       speed of sound wave

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Answer:

I think u are traeling at speed of light and not ur friend

Explanation:

4 0
3 years ago
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Addition of _____________ to pure water causes the greatest increase in conductivity.
postnew [5]
It's i<span>onic Compunds hope it helps!</span>
6 0
3 years ago
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The density of water is 1000 kg/m the pressure pf water at 10 m depth is about
puteri [66]

Answer:

pressure in liquids is given as:

P= hpg

where h is the depth

where p is the density

where g is 10

Explanation:

From the formula above

p = 10 X 1000 X 10

p = 100000N/m

6 0
2 years ago
A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does
alina1380 [7]

a)]An expression for the magnitude of charge transferred Q is Q = W/V.

b) The magnitude of the charge, in coulombs is  1.02 x 10⁻⁹ Coulomb.

c) Number of electrons in this are 63.75 x 10⁸ electrons.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does W= 1x10⁻⁶ J of work transferring the charge.

a) Work done = Charge x potential

W = Q x V

Q = W/V

b)Substitute the values into the expression, we have

|Q| =  1x10⁻⁶/9800

|Q| =  1.02 x 10⁻⁹ Coulomb

c) No of electrons  = total charge /charge on electron

n = 1.02 x 10⁻⁹/1.6 x 10⁻¹⁹

n = 63.75 x 10⁸ electrons

Learn more about electrons.

brainly.com/question/1255220

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6 0
2 years ago
How much work is done when 0.0042 C is moved through a potential difference of 12.0 V? Use W = qV A. 0.050 J B. 0.00035 J C. 290
Masja [62]

Answer:

Work done by charge (W) = 0.050 (Approx)

Explanation:

Given:

Charge (q) = 0.0042 C

Potential difference(V) = 12.0 V

Find:

Work done by charge

Computation:

Work done(W) = qV

Work done by charge (W) = (0.0042)(12)

Work done by charge (W) = 0.0504

Work done by charge (W) = 0.050 (Approx)

4 0
3 years ago
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