Answer:
The applied force on the vehicle is 5,000 N
Explanation:
From the question, we have the following parameters of the motion of the vehicle;
The form of the velocity with which the vehicle is travelling = Uniform velocity
The direction of motion of the vehicle = Along a straight and level stretch of the highway
The combined force which acts as resistance to the vehicle's motion = 5,000 N from rolling friction and resistance of the air opposite to the direction of motion
A vehicle travelling with uniform velocity has zero acceleration, therefore;
The acceleration of the vehicle, a = 0 m/s²
According to Newton's Second Law of Motion, we have;
Force, F = Mass, m × Acceleration, a
∴ The net force of acting on the vehicle, F = m × a
Where;
m = The mass of the vehicle
a = The acceleration of the vehicle = 0 m/s²
∴ F = m × 0 = 0
The net force on the vehicle = 0, therefore;
The applied force + The force of rolling friction and air resistance = 0
We therefore have;
The applied force + 5,000 N = 0
∴ The applied force = 0 - 5,000 N = -5,000 N
The applied force, F = 5,000 N in the direction of motion.
