The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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Answer:
Its C
Step-by-step explanation:
Answer:7
Step-by-step explanation:
Simplifying, 6x-2x-8 = 6 + 2x
4x -8 = 6 + 2x
2x =14
x=7
3(1)+4<span>≥ 13
7</span><span>≥ 13
No
3(2.5)+4</span><span>≥ 13
11.5</span><span>≥ 13
No
3(3)+4</span><span>≥ 13
13</span><span>≥ 13
Yes
{3, 4.5, 5}</span>
Answer: The proportion of employees who either have MBAs or are managers are 0.58.
Step-by-step explanation:
Since we have given that
Probability of employees having managerial positions = 67%
Probability of employees having MBA degrees = 58%
Probability of managers having MBA degrees = 67%
So, using probability formulas, we get that
Hence, the proportion of employees who either have MBAs or are managers are 0.58.
