Answer:
10x^2 y(2x + 3y)
Step-by-step explanation:
20x^3 y + 30x^2 y^2.
Factor 10x^2y out of 20x^3y.
10x^2 y (2x) + 30x^2 y^2
Factor 10x^2y out of 30x^2y^2.
10x^2 y (2x) + 10x^2 y (3y)
Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).
10x^2 y(2x + 3y)
you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y) than you factor out 10x^2y again and get 10x^2 y(2x + 3y) your third option
<span>Chris' average speed is 3.5mph:
Lets take Chris' brother speed = B
then Chris speed = (B+ 1) mph-------given in the question
and:
The average speed for covering 18 miles= chris' average speed + his brother's
average speed = (B+ 1) + B
since Speed = Distance covered / time taken
then average speed for 18 miles can also be found by: 18 miles/3 hours = 6 miles per hour
then we have; (B+ 1) + B = 6mph
(B +1) = (6-B)
B+B = 6-1=5
2B=5
B=5/2=2.5 mph (this is Chris' brother average speed)
Hence Chris' average speed is = B+1= 2.5+1= 3.5mph</span>
Answer:
5/8
Step-by-step explanation:
Try using Photomath for some it’s easy and faster than waiting for people to respond on here i can help u when I’m done w this test with the left side if ur still stuck
