G=Z6×Z2G=Z6×Z2 will do (where ZnZn denotes the cyclic group of order nn). As a direct product of cyclic (so abelian) groups, GG is again abelian. Given any element (x,y)∈G(x,y)∈G, the order of (x,y)(x,y) will be the least common multiple of the orders of x,y.x,y.
The order of xx must divide 66 and the order of yy must divide 2,2, so the order of (x,y)(x,y) is at most lcm(6,2)=6.lcm(6,2)=6. But |G|=|Z6|⋅|Z2|=6⋅2=12.|G|=|Z6|⋅|Z2|=6⋅2=12. Since no element of GG has order 12,12, then GG is not cyclic.
The volume of the sphere with a radius of 9 will be
v≈3053.63
Answer:
it will take 7 nights
Step-by-step explanation:
Step-by-step explanation:
(x-2)^3 = x^3-6x^2+12x-8
-(x^3-6x^2+12x-8)=
-x^3+6x^2-12x+8
-x^3+6x^2-12x+8 -5=
y=-x^3+6x^2-12x+3
I attached the picture
Answer:
7/10
Step-by-step explanation:
In 0.7 we will change the decimal to fraction. First we will write the decimal without the decimal point as the numerator. Now in the denominator, write 1 followed by one zeros as there are 1 digit in the decimal part of the decimal number. Therefore, we observe that 0.7 (decimal) is converted to 7/10 (fraction).
