All categories

3 years ago

In A Quiz Team a Scores -30 , 10 , 40 .

Mathematics

1 answer:

VLD [36.1K]3 years ago

3 0

Answer:

Team B scored more. By 10.

(Team A) -30 + 10 = -20 + 40 = 20

(Team B) 30 + 10 = 40 + -10 = 30

You might be interested in

Help on number 9 please!

lutik1710 [3]

2x+2

Work:

Factor 2x^2+10x+12: 2(x+2)(x+3)

Cancel all x+3, leaving 2(x+2)

2x+2

4 0

3 years ago

The low temperature last week in Iceland was-2.25. The low temperature this week was 1.25. What was the change in temperature fr

viktelen [127]

Answer:

The change in temperature from last week to this week=3.5

Step-by-step explanation:

To get the change in temperature from last week to this week, we need to take last week's temperature and subtract it from this week's temperature.

For example;

Change in temperature=This week's temperature-last week's temperature

where;

This week's temperature=-2.25

last week's temperature=1.25

replacing;

Change in temperature=(1.25)-(-2.25)=1.25+2.25=3.5

The change in temperature from last week to this week=3.5

6 0

4 years ago

Which expression is equivalent to 28 + 7? Prove your answer by showing your work.

OverLord2011 [107]

Answer:

ok so first lets find the answer to the original question

28+7=35

so lets find which one is equal to 35

7(4+1)=28+7=35 yes

4(7+1)=28+4=32 no

4(7+3)=28+12=40 no

7(4+7)=28+49=77 no

a is the answer

Hope This Helps!!!

6 0

3 years ago

Determine sen 0 y tan 0,si 0= 2/3 y cot 0>0

sdas [7]

Answer:

the answer of your question is 0

Step-by-step explanation:

the answer is 0

3 0

3 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

3 years ago