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Pie
3 years ago
13

Write True/False against the following statements and also correct the false statement.

Chemistry
2 answers:
Digiron [165]3 years ago
8 0
Hi! The answer would be true.
VladimirAG [237]3 years ago
5 0

Answer:

I think it is true you should go for true

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How many grams of magnesium are needed to completely react
Verizon [17]

97.22 grams of magnesium is needed.

<u>Explanation:</u>

The molar ratio of Mg to O2  to make MgO is 2:1

Here, we have 2 moles of O2, therefore we need 4 moles of Mg.

1 mol of Mg = 24.305 g

Therefore

4 moles of Mg = 4 \times 24.305 g

                        = 97.22 g

Hence we need 97.22grams of magnesium are needed to completely reactwith 2.00 mol of O2 in the synthesis reaction that producesmagnesium oxide.

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3 years ago
Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s−1 .
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The correct is this because they said
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Marie discovers boxes of elements in a storage room. The boxes do not say which elements they contain, but they do have informat
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The reactivity of metals increases as you move left in a period and as you move down in a group, so Marie needs to know the period and group of the element inside each box. Boxes that show locations in groups 1 or 2 or in period 8 contain the most reactive elements.

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4 years ago
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Our universe is made up of at least a
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Stars, milk, and fruits
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4 years ago
6 NaOH + 2 Al --&gt; 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?
tatyana61 [14]

Solution :

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of Na_3AlO_3.

So, 1 mole of Al produce 1 mole of  Na_3AlO_3.     .....statement 1)

Number of moles of Al in 258 gram of Al.

n = \dfrac{mass}{molar\ mass}\\\\n = \dfrac{258}{27}\ moles\\\\n = 9.556 \ moles

Therefore, from statement 1) number of moles of Na_3AlO_3 produced is also 9.556 moles.

7 0
3 years ago
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