It takes 281.7 kJ of energy to remove 1 mole of electrons from the atoms on the surface of lithium metal. If lithium metal is ir
1 answer:
Answer:
The maximum kinetic energy of electron is = 2.93 × Joule
Explanation:
We know that total energy
------------ (1)
Here h = plank's constant = 6.62 × J s
c = speed of light = 3 ×
= 261 nm = 261 ×
m
Put all these values in equation (1) we get
E = 7.6 × J
We know that
Total energy = Energy to remove an electron + K.E of electron
Energy to remove an electron =
Energy to remove an electron = 4.67 × J
K.E of electron = Total energy - Energy to remove an electron
K.E of electron = 7.6 × - 4.67 ×
K.E of electron = 2.93 × Joule
Therefore the maximum kinetic energy of electron is = 2.93 × Joule
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Answer:
2.5 % butane, 42.2 % pentane and 55.3 % hexane
Explanation:
Hello,
In this case, the mass balance for each substance is given by:
Whereas accounts for the fractions at the outlet distillate and
for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:
So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:
The total distillate flow:
And the total bottoms flow:
Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:
Then, the molar fraction of pentane and hexane:
Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.
NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.
Regards.