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olya-2409 [2.1K]
2 years ago
15

Calculate the ΔH o for the reaction: Fe3+(aq) + 3OH−(aq) → Fe(OH)3(s) ΔH o = kJ/mol Substance ΔH o f (kJ/mol) ΔG o f (kJ/mol) S

o (J/K·mol) Fe(s) 0 0 27.2 Fe2+(aq) −87.86 −84.9 −113.39 Fe3+(aq) −47.7 −10.5 −293.3 FeCl3(s) −400 −334 142.3 FeO(s) −272.0 −255.2 60.8 Fe2O3(s) −822.2 −741.0 90.0 Fe(OH)2(s) −568.19 −483.55 79.5 Fe(OH)3(s) −824.25 ? ? H(g) 218.2 203.2 114.6 H2(g) 0 0 131.0 H+(aq) 0 0 0 OH−(aq) −229.94 −157.30 −10.5
Chemistry
1 answer:
timofeeve [1]2 years ago
8 0

Answer:

ΔHr = -86.73 kJ/mol

Explanation:

Using Hess's law, you can calculate ΔH of any reaction using ΔH°f of products and reactants involed in the reaction.

<em>Hess law: ∑nΔH°f products - ∑nΔH°f reactants = ΔHr</em>

<em>-Where n are moles of reaction-</em>

For the reaction:

Fe³⁺(aq) + 3 OH⁻(aq) → Fe(OH)₃(s)

Hess law is:

ΔHr = ΔH°f Fe(OH)₃ - ΔH°f Fe³⁺ - 3×ΔH°f OH⁻

Where:

ΔH°f Fe(OH)₃: −824.25 kJ/mol

ΔH°f Fe³⁺: −47.7 kJ/mol

ΔH°f OH⁻: −229.94 kJ/mol

Replacing:

ΔHr = −824.25 kJ/mol - (−47.7 kJ/mol) - (3×-229.94 kJ/mol)

<em>ΔHr = -86.73 kJ/mol</em>

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For the reaction KClO2⟶KCl+O2 KClO2⟶KCl+O2 assign oxidation numbers to each element on each side of the equation. K in KClO2:K i
frosja888 [35]

Answer:

Explanation:

The formula of the reaction:

            KClO₂ → KCl + O₂

To assign oxidation numbers, we have to obey some rules:

  1. Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
  2. The charge on simple ions signifies their oxidation number.
  3. The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.

The oxidation number of K in KClO₂:

                                   K + (-1) + 2(-2) = 0

                                    K-5 = 0

                                    K = +5

The oxidation number of K in KCl:

                                K + (-1) = 0

                                K = +1

The oxidation number Cl in KClO₂ is -1

For Cl in KCl, the oxidation number is -1

For O in KClO₂, the oxidation number is (2 x -2) = -4

For O in O₂, the oxidation number is 0

K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.

O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.

7 0
3 years ago
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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 27.6 g of carbon were burned in the presence of
In-s [12.5K]

Answer:

The answer to your question is: 101.2 g of CO2

Explanation:

C = 27.6 g

O₂ = 86.5 g   remained 12.9 g

O₂ that reacted = 86.5 - 12.9 = 73.6 g

                     C     + O₂      ⇒        CO₂      The equation is balanced

                    27.6    73.6                 ?

MW               12        32                  44

Rule of three

                        12 g of C------------------  44 g  CO2

                       27.6 g C  ------------------    x

                  x = 27.6(44)/12 = 101.2 g of CO2

                       32 g of O2 ---------------    44 g of CO2

                        73.6 g of O2 ------------      x

                  x = 73.6(44)/32 = 101.2 g of CO2

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Concentrated sulfuric acid (18.3 M) has a density of 1.84 g/mL.
lianna [129]

The number of mole sulphuric acid in each mL of solution is 0.0183 mol/mL.

<h3>What is concentration?</h3>
  • Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume.
  • Mass concentration, molar concentration, number concentration, and volume concentration are four different categories of mathematical description.  
  • Any type of chemical mixture can be referred to by the term "concentration," however solutes and solvents in solutions are most usually mentioned.
  • There are different types of molar (quantity) concentration, including normal concentration and osmotic concentration.
<h3>How is concentration determined?</h3>
  • Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V.
  • To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.

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You have a 5-liter container with 1.30 x 1024 molecules of ammonia gas (NH3) at STP.
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Answer:

3). 1.30 × 10^(24) molecules

Explanation:

From avogadro's law which state that equal volume of all gases at the same temperature and pressure contain the same number of molecules.

We can relate it to this question as;

V₁/n₁ = V₂/n₂

Where;

V₁ is initial volume

n₁ is initial number of molecules

V₂ is final volume

n₂ is final number of molecules

Thus at STP, we have V₁ = V₂ and as such Plugging in the relevant values gives;

5/(1.30 x 10^(24)) = 5/n₂

n₂ = 1.30 x 10^(24) molecules

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