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Pepsi [2]
3 years ago
13

For the love of God please help me before my mom gets angry about my horrible grades

Physics
1 answer:
Maru [420]3 years ago
6 0

Answer:

Heat Lost = (120 - 12.6) deg * 170 g * S = `18260 gm-deg * S

Heat Gained = (12.6 - 10) deg * 200 gm* 1 cal/ gm-deg - 520 cal

S = 520 / 18260 cal / gm-deg = .0285 cal / gm-deg

Since Heat Lost = Heat Gained

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1.- Se desea elevar un cuerpo de 1500kg utilizando una elevadora hidráulica de plato grande
kvv77 [185]

Answer:

181.48 N

Explanation:

Calculate the area :

Area = pi * r² ;

pi = 3.14 ; r1 = 90cm /100 = 0.9m ; r2 = 10/100 = 0.1m

Area 1, A1 = 3.14 * 0.1² = 0.0314 m²

Area 2, A2 = 3.14 * 0.9² = 2.5434 m²

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5 0
3 years ago
A small object carrying a charge of -2.50 nc is acted upon by a downward force of 18.0 nn when placed at a certain point in an e
Vesna [10]
Missing question in the text:
"A.What are the magnitude and direction of the electric field at the point in question?

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<span>Solution:

A) A charge q </span>under an electric field of intensity E will experience a force F  equal to:

F=qE

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F=eE=1.6\cdot 10^{-19} C \cdot 7.2 V/m=1.15 \cdot 10^{-18} N

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7 0
3 years ago
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Answer:

I believe the answer is D.

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