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elixir [45]
3 years ago
11

How is the number 3450 written in scientific notation?

Physics
1 answer:
sammy [17]3 years ago
4 0

Answer:

B. 3.45 x 10^3

Explanation:

3450 = 3.45 \times  {10}^{3}  \\

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The density of air on the Earth decreases almost linearly with height from 1.22kgm–3 at sea level
Paraphin [41]
P = 10^5 - ρ (average)gh

where ρ (average) = average air density between 0 and 5000 m = (1.22+0.74)/2 = 0.98

we know g & h

I get P = 52470 Pa
3 0
3 years ago
__________ refers to an object positioned in the back of something or somebody ?
swat32
Posterior refers to an object positioned in the back of something or somebody, whereas if it's in the front, it's called anterior. 
5 0
3 years ago
A 1870 kg car traveling at 13.5 m/s collides with a 2970 kg car that is initally at rest at a stoplight. The cars stick together
Inga [223]

Answer:

The value  is \mu  = 0.72

Explanation:

From the question we are told that

   The mass of the first car is  m_1  =  1870\ kg

    the initial  speed of the car  is  u  =  13.5 \  m/s

    The  mass of the second car is  m_2 =  2970\  kg

    The distance move by both cars is  s =  1.93  m

Generally from the law of momentum conservation

    m_1 * u_1 + m_2 *  u_2  =  (m_1 + m_2 ) *  v_f

Here u_2  =  0 because the second car is at rest

and  v_f is the final  velocity of the the two car

So

    1870*  13.5+ 0=  ( 1870 + 2970 ) *  v_f      

=> v_f  =  5.22\  m/s

Generally from kinematic equation

    v_f^2 = u_2^2  +  2as

here a is the deceleration

So

    5.22^2 = 0  +  2 *a  *  1.93

=> a =  7.06 \  m/s^2

Generally the frictional  force is equal to the force propelling the car , this can be mathematically represented as

   F_f  =  F

Here  F is mathematically represented as

F =  (m_1 + m_2) *  a

F =  (1870 + 2970) *  7.06    

F =34170.4 \ N  

and

F_f  =  \mu *  (m_1 + m_2 ) *  g

F_f  =  47432 * \mu

So

47432 * \mu   = 34170.4

=> 47432 * \mu   = 34170.4

=> \mu  = 0.72

6 0
3 years ago
A test model for a new experimental gasoline engine does 45 J of work in one cycle for every 76 J of heat it takes in. What is t
kherson [118]

Answer:

The efficiency of the engine is 59.2%.

Explanation:

We have,

Work done by the gasoline engine is 45 J and the for every 76 J of heat it takes in.

It is required to find the efficiency of the engine. Efficiency of the engine is given by the ratio of work done to the heat taken i. Its formula is given by :

\eta=\dfrac{W}{Q}\\\\\eta=\dfrac{45}{76}\\\\\eta=0.592\\\\\eta=59.2\%

So, the efficiency of the engine is 59.2%.

3 0
3 years ago
How many seconds does it take for net force 20N to change the velocity to a 5kg mass by 2m/s?
castortr0y [4]

Answer:

0.5 second

Explanation:

We are given that

Force, F=20 N

Mass, m=5 kg

Change in velocity,=2m/s

We have to find the time taken to change the velocity .

We know that

Force, F=ma

Where

Acceleration, a=Change in velocity/time

a=\frac{2}{t}

Substitute the values

20=5\times \frac{2}{t}

t=\frac{5\times 2}{20}

t=0.5 s

5 0
3 years ago
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