Ask question

Ask question

All categories

3 years ago

12

How could you show the effect that gravity has on you? Name 2 ways and explain how they would show that gravity affects you.

1 answer:

Ilia_Sergeevich [38]3 years ago

8 0

1). Step on a bathroom scale & talk about where the force shown on the dial is coming from.

2). From the floor, climb up on to a chair, then explain why it's hard to do.

3). From up on the chair, take one giant step forward, then talk about what pulled you to the floor (and not to the ceiling or a wall).

You might be interested in

Una cámara fotográfica analógica (no digital) tiene dos lentes intercambiables. Uno de foco 55mm y el otro de 200 mm. Toma una f

Sergeu [11.5K]

Answer:

f = 55mm, h ’= -9.89 cm

f = 200 mm, h ’= 42.5 cm

Explanation:

For this exercise let's start by finding the distance to the image, using the equation of the constructor

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where f is the focal length, p and q are the distances to the object and image, respectively

lens with f₁ = 55mm = 0.55cm

$\frac{1}{q} = \frac{1}{f} - \frac{1}{p}$

$\frac{1}{q_1}$ = $\frac{1}{0.55} - \frac{1}{10}$

$\frac{1}{q_1}$ = 1.718

q₁ = 0.582 m

lens with f₂ = 200mm = 2m

$\frac{1}{q_2}$ = $\frac{1}{2} - \frac{1}{10}$

$\frac{1}{q_2}$ = 0.4

q₂ = 2.5 m

the magnification of a lens is given by

m = $\frac{h'}{h} = - \frac{q}{p}$

h ’= $- \frac{q}{p} \ h$

let's calculate for each lens

f = 55mm

h '= - 0.582 / 10 1.7

h ’= 0.0989 m

h ’= -9.89 cm

f = 200 mm

h '= - 2.5 / 10 1.7

h ’= -0.425 m

h ’= 42.5 cm

The negative sign indicates that the image is real and inverted

4 0

3 years ago

The exact speed of an object in a specific instant is?

GarryVolchara [31]

Im not so sure but it should be the
instantaneous speed

3 0

4 years ago

Read 2 more answers

Which oftthe following is the least reliable source of background information for a scientific project? General internet site, g

kenny6666 [7]

General internet site

7 0

3 years ago

A uniform magnetic field B=5.210 T is perpendicular to the plane of the paper (into the page). The current-carrying wire of valu

ehidna [41]

Answer:5.21 N

Explanation:

Given

B=5.210 T

I=2 A

L=0.5 m

Given Wire is perpendicular to Magnetic field

$\theta =90^{\circ}$

$F=IL\times B$

$F=BIL sin\theta$

$F=5.210\cdot 2\cdot 0.5 sin(90)$

F=5.210 N

as 1 Tesla =1 N/A/m

4 0

3 years ago

Express the measurement 0.00000575 into scientific notation.

g100num [7]

Answer: = 5.75 × 10 -6

Explanation:

= 5.75 × 10-6

(scientific notation)

= 5.75e-6

(scientific e notation)

= 5.75 × 10-6

(engineering notation)

(millionth; prefix micro- (u))

= 0.00000575

(real number)

7 0

3 years ago