Answer:
paper or soft material used to cover or enclose something.
i think the answer is this
Answer:
The main difference between second generation (2G) and third generation (3G) technology is data. 2G services were developed with mostly voice services in mind, but are capable of providing relatively slow (14.4kbps) speed data services.
Answer:
See explaination
Explanation:
Given a set U which is the set of magnets where each magnet representing a symbol, but are accepted more copies of the same symbol which we number arbitrarily 1,2,3,. ... For example if we had two copies of the symbol A, we would have elements A 1 ,A 2 ) and subsets S 1 ,...S n which represent words formed from the magnets that Madison knows how to spell. Note that if ‘’CAT” was a word in Madison’s vocabulary, then both of the sets C,A 1 ,T and C,A 2 ,T would appear among the S i . We are interested in the maximum number of disjoint sets (which correspond to words in Madison’s vocabulary that can be simultaneously spelled out by the magnet pieces).
We reduce Independent Set (IS) to Set Packing. Given an instance of IS ( G,k ), we set U to be the set of edges of G . For each vertex v i , we introduce a set S i = { e : e = ( v i ,x ) } which has one element for each edge incident to v i . We claim that G has an independent set of size k iff there are k disjoint sets among the S i . Indeed, if I is an independent set of size k then the k sets S v for v ∈ I have no common elements. Also, if { S i 1 ,...,S i k } are k disjoint sets then the vertices v i 1 ,...,v i k have no edges between them thus they form an independent set of size.
Answer:
def count_digits(val):
count_lst = [0] * 10
val = str(val)
for digit in val:
if digit == "0":
count_lst[0] += 1
elif digit == "1":
count_lst[1] += 1
elif digit == "2":
count_lst[2] += 1
elif digit == "3":
count_lst[3] += 1
elif digit == "4":
count_lst[4] += 1
elif digit == "5":
count_lst[5] += 1
elif digit == "6":
count_lst[6] += 1
elif digit == "7":
count_lst[7] += 1
elif digit == "8":
count_lst[8] += 1
elif digit == "9":
count_lst[9] += 1
return count_lst
Explanation:
Create a function called count_digits that takes one integer parameter, val
Initialize a count_list that will hold the counts for the digits in the val
Convert val to string
Initialize a for loop that iterates through the val
Inside the loop, check each digit in val and increment its corresponding position in the count_list
When the loop is done, return the count_list