Answer:
0.1994 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 166 pounds
Standard Deviation, σ = 5.3 pounds
Sample size, n = 20
We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =

P(sample of 20 boxers is more than 167 pounds)
Calculation the value from standard normal z table, we have,
0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds
Answer:
It took him 12 hours
Step-by-step explanation:
480 / 40=12
<span>x in (-oo:+oo)
((5-9*x)^1)/2 = ((4*x+3)^1)/2 // - ((4*x+3)^1)/2
((5-9*x)^1)/2-(((4*x+3)^1)/2) = 0
(5-9*x)/2-((4*x+3)/2) = 0
(5-9*x)/2+(-1*(4*x+3))/2 = 0
5-1*(4*x+3)-9*x = 0
2-13*x = 0
(2-13*x)/2 = 0
(2-13*x)/2 = 0 // * 2
2-13*x = 0
2-13*x = 0 // - 2
-13*x = -2 // : -13
x = -2/(-13)
x = 2/13
x = 2/13</span>
Answer:

Step-by-step explanation:
-4x + y
Plug in your values for x and y
-4 (5/4) + (1/5)
-20/4 + 1/5
-5 + 1/5
= - 4 4/5
Answer:
The quotient of 7 and 14 is 2..