Answer:
The answer to your question is C = 1.116 J/g°C
Explanation:
Data
Q = 400 J
mass = 5.6 g
Temperature 1 = T1 = 23°C
Temperature 2 = T2 = 87°C
Specific heat = C = ?
Formula
Q = mC(T2 - T1)
- Solve for C
C = Q / m(T2 - T1)
- Substitution
C = 400 / 5.6 (87 - 23)
- Simplification
C = 400 / 5.6(64)
C = 400 / 358.4
- Result
C = 1.116 J/g°C
Disagree is the awnser to this question
Answer:
449.5 g
Explanation:
Silver sulfate- Ag2SO4
M(Ag)=107 g/mol => M(Ag2)=214 g/mol
M(S)=32 g/mol
M(O)=16 g/mol => M(O4)=64 g/mol
M(Ag2SO4)=310 g/mol
n=1.45 mol
m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g
Answer:
Extensive properties, such as mass and volume depend on the amount of substance present and are not useful in the identification of a substance. In this experiment, we will use three properties to identify a liquid substance: solubility, density and boiling point.
Answer:
love triangle?- orr they can figure something out
