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miskamm [114]
3 years ago
11

An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined

to be 6.5e-07. The pH at the second equivalence point of the titration is measured as 8.181. What is Ka3 for this triprotic acid
Chemistry
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

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In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 gram
kherson [118]

This question is incomplete, the complete question is;

In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 grams. If the % composition of the acetanilide impurity in the sample is 6.3 %, what is the minimum amount in mL of solvent (water) required for the recrystallization

Compound      Solubility in water at 25°C      Solubility in water at 100°C

Benzoic Acid      0.34 g/100mL                           5.6 g/100mL

Acetanilide         0.53 g/100mL                           5.5 g/100mL

Answer:

The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL

Explanation:

Given the data in the question;

mass of sample = 5 g

percentage composition of the acetanilide impurity = 6.3%

mass of the acetanilide in impure sample will be;

⇒ 6.3% × 5 g = 0.315 g

Mass of benzoic acid in impure sample;

⇒ 5 g - 0.315 g = 4.685 g

now, solubility in water at 100°C for benzoic acid = 5.6 g/100mL

hence 4.685 g of benzoic acid is soluble in x mL

x = [ 100 mL × 4.685 g ] / 5.6 g

x = 83.66 ≈ 84 mL

Also, solubility in water at 100°C for acetanilide = 5.5 g/100mL

hence 0.315 g of benzoic acid is soluble in x mL

x = [ 100 mL × 0.315 g ] / 5.5 g

x = 5.727 ≈ 6 mL

So, the minimum amount in mL of solvent (water) required for the recrystallization will be;

⇒ 85 mL + 6 mL = 91 mL

The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL

5 0
3 years ago
An element’s properties can be predicted from _____.
jek_recluse [69]
It can be predicted from the location on the periodic table.
5 0
2 years ago
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Consider the elements bromine and chlorine; which element has a larger ionic radius?
Nikolay [14]
Not 100% be Im pretty positve its Bromine

6 0
3 years ago
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274 l is equal to: 2.74 ml 27.4 ml 274 ml 2,740 ml
devlian [24]
1 L ---------- 1000 mL
274 L ------- ??

274 x 1000 / 1 => 2,740 mL

hope this helps!
8 0
3 years ago
Alkaline earth metals are involved in two key diagonal relationships in the periodic table.(a) Give the two pairs of elements in
Molodets [167]

Two alkaline earth metals; Be and Mg exhibit a diagonal relationship. The pair of elements are Be-Al and Mg-Li is Be-Al and Mg-Li.

Six elements make up the majority of alkaline earth metals (Group 2): beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). Compared to the elements in Group 1, this group typically contains smooth, silver metals with a less metallic character. Heavy metals like Ca, Sr, Ba, and Ra are equally as reactive as Alkali Metals Group 1 despite sharing many characteristics with that group. All elements found in alkaline earth metals contain two electrons in their valence shells, giving them an oxidation state of +2. This makes it possible for metals to shed electrons with ease, allowing them to create compounds with more stable ionic connections.

Two alkaline earth metals; Be and Mg exhibit a diagonal relationship. The pair of elements are Be-Al and Mg-Li.

To learn more about alkaline earth metals refer the link:

brainly.com/question/12835232

#SPJ4

6 0
1 year ago
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