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miskamm [114]
3 years ago
11

An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined

to be 6.5e-07. The pH at the second equivalence point of the titration is measured as 8.181. What is Ka3 for this triprotic acid
Chemistry
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

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when you decrease the distance between two magnets that are repelling, you increase the magnetic force. True or false?
kupik [55]

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False that would be crazy but cool

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3 years ago
Read 2 more answers
What do these elements make:<br> neodymium, rhenium and sulfur
LiRa [457]

Answer:

Neodymium makes flints inside of lighters. It also takes away the green color off of glass. Rhenium is added with tungsten and molybdenum which makes filaments for lamps. Sulfur makes sulfuric acid which makes batteries and cleaners and can process ores.

Explanation:

An interesting fact for each element:

Neodymium is known for the atomic symbol Nd and the atomic number 60.

Rhenium is known for the atomic symbol Re and the atomic number 75.

Sulfur is known for the atomic symbol S and the atomic number 16.

I hope the Answer answers your question. I gave you some facts to remember those elements in the periodic table!

6 0
2 years ago
Extend your thinking: The slow decay of radioactive materials can be used to find the age of rocks, fossils, and archaeological
lisov135 [29]

The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

<h3>What is the half-life of a radioactive material?</h3>

The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.

The half-life, t_\frac{1}{2}, the age, t, and amount remaining, A_{r}, of a radioactive material are related by the formula below:

  • t = \frac{t_\frac{1}{2}*A_{r}}{-ln2}

Half-life of carbon-14 = 6000 years

For the Egyptian papyrus with 63% of its original carbon-14 atoms:t = \frac{6000*0.63}{-0.63} = 4000\:years

For the Aboriginal charcoal with 22% of its original carbon-14 atoms:

t = \frac{6000*0.22}{-0.63} = 13106.5\:years

For the Mayan headdress with 79% of its original carbon-14 atoms:

t = \frac{6000*0.79}{-0.63} = 2040\:years

Neanderthal skull with 3% of its original carbon-14 atoms:

t = \frac{6000*0.03}{-0.63} = 30353\:years

Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

Learn more about half-life at: brainly.com/question/26689704

#SPJ1

6 0
2 years ago
What is the major product in this reaction
Butoxors [25]

Answer:

I think option A is right answer

4 0
3 years ago
Significant Figures: How many significant figures<br> are in 865,010?
Harrizon [31]

Answer: There are five significant figures in 865,010.

Explanation:

When a degree of accuracy is stated by each digit present in a mathematical figure then it is called a significant figure.

Rules for counting significant figures is as follows.

  • Any non-zero digits and zeros present between a non-zero figure are counted. For example, 3580009 has seven significant figures.
  • Trailing zeros are counted in a non-zero figure. For example, 0.00250 has three significant figures.
  • Leading zeros are not counted. For example, 0.0025 has two significant figures.

So, in the given figure 865010 has five significant figures and the trailing zero will not be counted.

Thus, we can conclude that there are five significant figures in 865,010.

7 0
3 years ago
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