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zzz [600]
3 years ago
15

PLEASE HELP ME I DONT EVEN KNOW IF I CIRCLES THE RIGHT THING!!

Chemistry
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

why are anime and cartoons awesome? wt..f

Explanation:

I dont got that are you serious or making fun?

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If ammonia were formed from dalton's simplest formula of one atom of each element, what would he have concluded about the relati
baherus [9]
He would have concluded that the order of operations would be different. This therefore would affect the periodic table's order. 
8 0
3 years ago
What would be the volume in liters of 640g of oil if the density of the oil is 0.8g/mL
Alexus [3.1K]

Hey there!

Mass = 640 g

Density = 0.8 g/mL

Volume = ?

Therefore:

D = m / V

0.8 = 640 / V

V = 640 / 0.8

V = 800 mL

hope that helps!

4 0
3 years ago
Read 2 more answers
I have no idea on how to do this here is the question (For the following pairs of atoms, show how they transfer valence electron
Maru [420]

Answer:

uhh

Explanation:

i hope you find this answer

3 0
3 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
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What did sewage treatment in Ancient Rome and 19th century London have in common? How effective was this strategy and why?
anygoal [31]

Yea pretty much

Explanation:

4 0
3 years ago
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