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zzz [600]
3 years ago
15

PLEASE HELP ME I DONT EVEN KNOW IF I CIRCLES THE RIGHT THING!!

Chemistry
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

why are anime and cartoons awesome? wt..f

Explanation:

I dont got that are you serious or making fun?

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When the first ball in a Newton's cradle is pulled back and released, it causes the final ball to move. What does this example o
bazaltina [42]

Answer:

<h3>A. </h3>

Explanation:

Mechanical energy is energy in motion is the example of mechanical energy⚡

7 0
3 years ago
How many atoms of oxygen (o)are present 2naOH+H2SO4 2H2O+Na2SO4
Dafna1 [17]

Answer:

10

Explanation:

6 0
3 years ago
Examine the given reaction. NH4NO3(s) → NH4+(aq) + NO3–(aq) ΔH° = 25.45 kJ/mol ΔS° = 108.7 J/mol·K Which of the given is correct
kobusy [5.1K]

Answer:

B)−6,942 J /mol

Explanation:

At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:

ΔG = ΔH - TΔS

Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.

Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):

ΔG = ΔH - TΔS

ΔG = 25450J/mol - 298K×108.7J/molK

ΔG = -6942.6J/mol

Right solution is:

<h3>B)−6,942 J /mol</h3>

8 0
3 years ago
Explain why a solution has a lower boiling point than the pure solvent
KonstantinChe [14]
Because the intention is to boil the solution, the purpose of the solvent is to dissolve so it has a higher boiling point so ensure it stays in liquid form and doesn't evaporate into a gas

also, a pure solvent is made of 1 substance so it has 1 boiling point and the solution must evaporate/boil first
7 0
4 years ago
The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this
nevsk [136]

Answer:

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }

The given reaction involves the decomposition of H2O into H2 and O2

2H_{2}O\rightleftharpoons 2H_{2} + O_{2}

The equilibrium constant is expressed as :

Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Since Keq = 5.31*10^-10

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

3 0
3 years ago
Read 2 more answers
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