Answer:
the answer is 12
Step-by-step explanation:
Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:

Substitute the respective values in the above formula.



Hence, the required probability is 0.55404.
Answer:
10
Step-by-step explanation:
Given expression is
.
is a complex expression.
The value of<em> i </em>is –1.
By definition of absolute value, 
Now, substitute
in the above formula.
(since <em>i </em>= –1)
(since
and
)
(Square root of 100 is 10)
= 10
Hence, the value of the expression
is 10.
To find the answer you do 19×19= 361 and do 361×3.14= 1,133.54 The area of the stage is 1,133.54
Answer:
$1300
Step-by-step explanation:
The extruder yields a revenue of $200per hour
Y denotes the number of breakdown per day.
The daily revenue generated is given as
R = 1600 - 50Y^2
We have an average of 2 breakdown per day
Lamda = 2
Represent lamda as β
E(Y) = β
E(Y(Y-1)) = β^2
E(Y^2) = E[Y(Y-1)] + E(Y)
= β^2 + β
E(R) = E(1600 - 50Y^2)
= 1600 - 50E(Y^2)
= 1600 - 50(β^2 +β)
Recall that β = lamda = 2
= 1600 - 50(2^2 + 2)
= 1600 - 50(4+2)
= 1600 - 50(6)
= 1600 - 300
= 1300
$1300
The expected daily revenue of the extruder is $1300