Answer:
Step-by-step explanation:
Chill out, what ya yellin' for?
Lay back, it's all been done before
And if, you could only let it be, you will see
I like you the way you are
When we're driving in your car
And you're talking to me one on one, but you become
Somebody else
'Round everyone else
You're watching your back
Like you can't relax
You try to be cool
You look like a fool to me
Tell me
Answer:-25+-12
Step-by-step explanation:so I made x value as 5 so I multiplied -5x5 and it's -25 then I multiplied -4x-7 and that's -12 so the equivalent expression for my way is -25+-12
Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.
Combined Area = (2x + 26)*(2x + 8) = 1008
2x*(2x + 8) + 26*(2x + 8 ) = 1008
4x² + 16x + 52x + 208 = 1008
4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0. Divide through by 4.
x² + 17x - 200 = 0 . This is a quadratic equation.
Multiply first and last coefficients: 1*-200 = -200
We look for two numbers that multiply to give -200, and add to give +17
Those two numbers are 25 and -8.
Check: 25*-8 = -200 25 + -8 = 17
We replace the middle term of +17x in the quadratic expression with 25x -8x
x² +17x - 200 = 0
x² + 25x - 8x - 200 = 0
x(x + 25) - 8(x + 25) = 0
(x+25)(x -8) = 0
x + 25 = 0 or x - 8 = 0
x = 0 -25 x = 0 + 8
x = -25 x = 8
The width of the path can not be negative.
The only valid solution is x = 8.
The width of the path is 8 meters.
Answer:
F. 
C. 
B. 
Step-by-step explanation:
You first need to find the linear equation<em> </em>[in <em>Slope-Intercept</em><em> </em><em>Form</em><em> </em>of course] of this graph, which is 
To do this, starting from the y-intercept of 
you do 
by either moving two blocks <em>south</em><em> </em>over one block <em>way</em><em> </em>or two blocks <em>north</em><em> </em>over<em> </em>one block <em>east</em> [<em>west</em><em> </em>and <em>south</em><em> </em>are negatives]. This will give you your <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] of 2.
* 
I am joyous to assist you anytime.
