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2 years ago

The measure of ∠BCD is 120°. The measure of ∠ABC is 85°.

Mathematics

1 answer:

saveliy_v [14]2 years ago

4 0

Answer:

Step-by-step explanation:

Chill out, what ya yellin' for?

Lay back, it's all been done before

And if, you could only let it be, you will see

I like you the way you are

When we're driving in your car

And you're talking to me one on one, but you become

Somebody else

'Round everyone else

You're watching your back

Like you can't relax

You try to be cool

You look like a fool to me

Tell me

You might be interested in

Please help I asked this question earlier and nobody answered! :(

tatiyna

Answer:

Step-by-step explanation:

One way to tell is to put both equations into slope-intercept form. That form is usually written $y=mx+b$ where m is the slope and b is the y-intercept.

Solve the first equation for y.

$6x+2y=5 \\ 2y=-6x+5 \\ y=-3x+5/2$

The slope of this line is -3, and its y-intercept is 5/2.

Solve the second equation for y.

$y+3x=2\\y=-3x+2$

The slope of this line is -3 and its y-intercept is 2.

The lines are parallel because they have the same slope and different y-intercepts. There is no solution to the system.

8 0

3 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

4 0

3 years ago

Determine whether the function is odd, even, neither, or can’t be determined: g(x) = x2 + x Question options:

Anastasy [175]

I have already done this question. The correct answer is c

7 0

3 years ago

Read 2 more answers

Explain how you know these two figures are similar

ICE Princess25 [194]

Is there a picture to go with it

4 0

3 years ago

a customer buys a diiferent book that has an original selling price of $38 the books is discounted 25% the customer must pay a 6

Nimfa-mama [501]

Answer: 30.21$
Explanation:
1. 38• 0.25(25%)=28.50
2. 28.50•0.06(6)=1.71 ( the sales taxes)
3. 28.50+1.71=30.21$
Hope this helps. If it’s correct please tell me.

7 0

3 years ago