Answer:
The correct option is C. 9
Step-by-step explanation:
From the graphs shown in the attached file we can see that the maximum number of shoes bought were of size 9. On both days the number of size 9 shoes bought was 5 which was the highest number of shoes bought for any size shoe. Therefore since size 9 sell the most on both days the owner should stock most of size 9 shoes in the store's inventory.
Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.