C6H14 (g) + O2 (g) -> H20 (g) + CO2 (g)<br> chemical reaction?

During the fission of uranium-235, neutrons are released and a small amount of mass is converted to energy. How many neutrons ar

Ksenya-84 [330]

143 neutrons in uranium 235

5 0

2 years ago

A helium-filled weather balloon has a volume of 793 L at 16.9°C and 759 mmHg. It is released and rises to an altitude of 4.05 km

mariarad [96]

<h3>Answer:</h3>

1082.96 L

<h3>Explanation:</h3>

We are given;

Initial volume of helium gas, V1 = 793 L
Initial temperature, T1 = 16.9°C

But, K = °C + 273.15

Thus, initial temperature, T1 is 290.05 K
Initial pressure, P1 = 759 mmHg
New pressure at 4.05 km, P2 = 537 mmHg
New temperature at 4.05 km, T2 = 7.1 °C

= 280.25 K

Assuming we are required to calculate the new volume at the height of 4.05 km

We are going to use the combined gas law.

According to the combined gas law;

$\frac{P1V1}{T1}=\frac{P2V2}{T2}$

Rearranging the formula;

$V2=\frac{P1V1T2}{P2T1}$

$V2=\frac{(759mmHg)(793L)(280.25K)}{(537mmHg)(290.05K)}$

$V2=1082.96L$

Therefore, the new volume of the balloon at the height of 4.05 km is 1082.96 L

6 0

3 years ago

Hello need help nitrogen is chemically insert gas why give reason need explanation (人*´∀｀)｡*ﾟ+

AlladinOne [14]

Answer:

Nitrogen is inert because its p-subshell is half-filled due to it has maximum exchange energy. Thus it is exists in stable form as like inert gas and it form triple bond (N≡N). N2 molecules is very stable and its dissociation energy is 225kcal/mol.

Hope it's helpful

5 0

2 years ago

Read 2 more answers

Calculate the volume of air in liters that you might inhale (and exhale) in 12.0 hours. Assume that each breath has a volume of

zloy xaker [14]

Taking into account the rule of three, the volume of air that you inhale (and exhale) in 12.0 hours is 4,384.8 liters.

<h3>Rule of three</h3>

In first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: $x=\frac{cxb}{a}$

<h3 /><h3>Volume of air inhaled and exhaled</h3>

To calculated the volume of air inhaled and exhaled in 12 hours, you know that each breath has a volume of 0.435 liters, and that you are breathing 14 times a minute.

The you can apply the following rule of three: If each breath has a volume of 0.435 liters, 14 breaths have how much volume?

$volume=\frac{14 breathsx0.435 liters}{1 breath}$

<u><em>volume= 6.09 liters</em></u>

So, 14 breaths a minute have a volume of 6.09 liters, this means that in 1 minute you inhale and exhale 6.09 liters.

Now, knowing that 1 hour has 60 minutes, 12 hours has 720 minutes. So you can apply the following rule of three: in 1 minute you inhale and exhale 6.09 liters, in 720 minutes you inhale and exhale how much volume?

$volume=\frac{720 minutesx6.09 liters}{1 minute}$

<u><em>volume= 4,384.8 liters</em></u>

In summary, the volume of air that you inhale (and exhale) in 12.0 hours is 4,384.8 liters.

Learn more with this similar problems:

brainly.com/question/4807720?referrer=searchResults

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3 0

2 years ago

What are some differences between an “ideal” gas and real gases?

gogolik [260]

Answer:

The Ideal Gases are described under the standard conditions to eliminate as many variables as possible.

Explanation:

P*V = n*R*(temp final-temp initial) There are standard conditions for the relationships between pressure (P), Volume (V), number of moles (n), and the temperature in Kelvin (K) or Celsius (C).

7 0

3 years ago

C6H14 (g) + O2 (g) -> H20 (g) + CO2 (g) chemical reaction?