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quester [9]
3 years ago
12

A landscaping company placed two orders with a nursery. The first order was for 13 shrubs and 4 trees and totaled 487. The secon

d order was for 6 scrubs and 2 trees,and totaled 232. The bills do not list the per-item price. What were the costs of one shrub of one tree?
Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

Cost of shrubs = 23

Cost of tree = 47

Step-by-step explanation:

Let

Cost of shrubs = x

Cost of tree = y

13x + 4y = 487 (1)

6x + 2y = 232 (2)

Multiply (2) by 2

12x + 4y = 464 (3)

13x + 4y = 487 (1)

Subtract (3) from (1)

13x - 12x = 487 - 464

x = 23

Substitute x = 23 into (2)

6x + 2y = 232 (2)

6(23) + 2y = 232

138 + 2y = 232

2y = 232 - 138

2y = 94

y = 94/2

= 47

y = 47

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Is 301 in the sequence below?<br> -9, -5,-1,3,7,...
dusya [7]

Answer:

no

Step-by-step explanation:

Establish the nth term formula

There is a common difference d between consecutive terms, that is

d = - 5 - (- 9) = - 1 - (- 5) = 3 - (- 1) = 7 - 3 = 4

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 9 and d = 4 , then

a_{n} = - 9 + 4(n - 1) = - 9 + 4n - 4 = 4n - 13

Equate 4n - 13 to 301

4n - 13 = 301 ( add 13 to both sides )

4n = 314 ( divide both sides by 4 )

n = 78.5

Since n is not an integer then 301 is not in the sequence

3 0
2 years ago
Which expressions are equivalent to 2 (three-fourths x 7) minus 3 (one-half x minus 5)? Check all that apply. -1 29 2 (three-fou
Otrada [13]

The expression is equivalent to \rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\.

<h2 /><h2>Given that</h2>

Expression; \rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)

<h3>We have to determine</h3>

Which expressions are equivalent to the given expression.

<h3>According to the question</h3>

Expression; \rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)

To solve the given expression follow all the steps given below.

By applying the distributive property of multiplication;

\rm a(b+c) = ab+ac

Then,

The equivalent expression is,

\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\\&#10;\\&#10;\rm (2 \times \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\&#10;\\&#10;2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\

Hence, the expression is equivalent to \rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\.

To know more about Equation click the link given below.

brainly.com/question/13174611

5 0
2 years ago
Please help me with this problem
aleksandr82 [10.1K]

9514 1404 393

Answer:

  (x, y) = (-3, -13) or (-8, -23)

Step-by-step explanation:

The values for y can be equated and the resulting quadratic solved by factoring.

  2x -7 = x^2 +13x +17

  0 = x^2 +11x +24 . . . . . . subtract 2x-7

  0 = (x +8)(x +3) . . . . . . . .factor*

The values of x that make these factors zero are x=-8 and x=-3. The corresponding values of y are ...

  y = 2(-8) -7 = -23

  y = 2(-3) -7 = -13

The solutions are ...

  (x, y) = (-8, -23) and (-3, -13)

_____

* The constants in the binomial factors are factors of 24 that total 11. You know that ...

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The sums of these factors are 25, 14, 11, 10. The factors 3 and 8 are the constants in the binomial factors of the quadratic.

"24" is the constant in the quadratic. "11" is the coefficient of the x term.

6 0
3 years ago
Convert 150 g/L to the unit g/mL. .
Alekssandra [29.7K]
G/L=1000*g/mL, since 1 mL = 1/1000 of a litre. 
<span>Therefore, 150g/L=150 000 g/mL.</span>
7 0
2 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
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