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quester [9]
3 years ago
12

A landscaping company placed two orders with a nursery. The first order was for 13 shrubs and 4 trees and totaled 487. The secon

d order was for 6 scrubs and 2 trees,and totaled 232. The bills do not list the per-item price. What were the costs of one shrub of one tree?
Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

Cost of shrubs = 23

Cost of tree = 47

Step-by-step explanation:

Let

Cost of shrubs = x

Cost of tree = y

13x + 4y = 487 (1)

6x + 2y = 232 (2)

Multiply (2) by 2

12x + 4y = 464 (3)

13x + 4y = 487 (1)

Subtract (3) from (1)

13x - 12x = 487 - 464

x = 23

Substitute x = 23 into (2)

6x + 2y = 232 (2)

6(23) + 2y = 232

138 + 2y = 232

2y = 232 - 138

2y = 94

y = 94/2

= 47

y = 47

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Part A: Max rented a motorbike at $465 for 5 days. If he rents the same motorbike for a week, he has to pay a total rent of $625
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Answer: Our required equation will be

y-80x=65

Step-by-step explanation:

Since we have given that

Number of days Max rented a motorbike at $465 = 5 days

Number of days Max rented a motorbike at $625 = 7 days

According to question, we'll use " Equation of line using two points "

(y-y_0)=\frac{y_2-y_1}{x_2-x_1}(x-x_0)\\\\(y-465)=\frac{625-465}{7-5}(x-5)\\\\(y-465)=80(x-5)\\\\y-465=80x-400\\\\y-80x=-400+465\\\\y-80x=65

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y-80x=65

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?

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Step-by-step explanation:

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3 years ago
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The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

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Answer:

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Step-by-step explanation:

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