Answer:
no
Step-by-step explanation:
Establish the nth term formula
There is a common difference d between consecutive terms, that is
d = - 5 - (- 9) = - 1 - (- 5) = 3 - (- 1) = 7 - 3 = 4
This indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 9 and d = 4 , then
= - 9 + 4(n - 1) = - 9 + 4n - 4 = 4n - 13
Equate 4n - 13 to 301
4n - 13 = 301 ( add 13 to both sides )
4n = 314 ( divide both sides by 4 )
n = 78.5
Since n is not an integer then 301 is not in the sequence
The expression is equivalent to 
.
<h2 /><h2>Given that</h2>
Expression; 
<h3>We have to determine</h3>
Which expressions are equivalent to the given expression.
<h3>According to the question</h3>
Expression;
To solve the given expression follow all the steps given below.
By applying the distributive property of multiplication;
Then,
The equivalent expression is,
Hence, the expression is equivalent to .
To know more about Equation click the link given below.
brainly.com/question/13174611
9514 1404 393
Answer:
(x, y) = (-3, -13) or (-8, -23)
Step-by-step explanation:
The values for y can be equated and the resulting quadratic solved by factoring.
2x -7 = x^2 +13x +17
0 = x^2 +11x +24 . . . . . . subtract 2x-7
0 = (x +8)(x +3) . . . . . . . .factor*
The values of x that make these factors zero are x=-8 and x=-3. The corresponding values of y are ...
y = 2(-8) -7 = -23
y = 2(-3) -7 = -13
The solutions are ...
(x, y) = (-8, -23) and (-3, -13)
_____
* The constants in the binomial factors are factors of 24 that total 11. You know that ...
24 = 1×24 = 2×12 = 3×8 = 4×6
The sums of these factors are 25, 14, 11, 10. The factors 3 and 8 are the constants in the binomial factors of the quadratic.
"24" is the constant in the quadratic. "11" is the coefficient of the x term.
G/L=1000*g/mL, since 1 mL = 1/1000 of a litre.
<span>Therefore, 150g/L=150 000 g/mL.</span>
Answer:
The standard error of the mean is 0.0783.
Step-by-step explanation:
The Central Limit Theorem helps us find the standard error of the mean:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
.
The standard deviation of the sample is the same as the standard error of the mean. So
In this problem, we have that:
So
The standard error of the mean is 0.0783.
