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3 years ago

12

What is the noble gas electron configuration of bismuth (Bİ)?

2 answers:

iVinArrow [24]3 years ago

8 0

Answer: [Xe] 6s^2 6p^3

Explanation: The noble gases are on the last column of the periodic table and Xenon (Xe) is the noble gas before Bismuth (Bi). Then you go down to the next row which is 6s^2 and 6p^3.

krek1111 [17]3 years ago

4 0

Answer:

The correct answer is {Xe] 4f14 5d10 6s2 6p3

Explanation:

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In the lab, frank has two solutions that contain alcohol and is mixing them with each other. he uses 100 milliliters less of sol

VladimirAG [237]

Solution B (17% alcohol) = x ml
Solution A (13% alcohol) = (x-100) ml

0.17x ml alcohol in Solution B
0.13(x-100) ml alcohol in Solution A

0.17x + 0.13(x-100) = 347
0.17x+0.13x-13=347
0.3x = 360
x=360/0.3=3600/3=1200 ml solution B

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3 years ago

Read 2 more answers

How many grams of potassium bromide, KBr, are in 100mL of a 0.50 M solution?

VMariaS [17]

Answer:

5.95g

Explanation:

1 $dm^{3}$ = 1000 mL

∴ 100 mL = 100 ÷ 1000 = 0.1 $dm^{3}$

Volume = <u>0.1 </u> $dm^{3}$ <u />

Concentration = <u>0.5 M</u>

Concentration = $\frac{No. of moles}{volume}$

0.5 = $\frac{x}{0.1}$

No. of moles = 0.5 x 0.1 = <u>0.05 moles</u>

No. of moles = $\frac{mass}{mass. in. 1. mole}$

Mass in 1 mole of KBr = 39 + 80 = 119g (39 is the mass of potassium and 80 is the mass of bromine)

0.05 = $\frac{x}{119}$

x = 119 × 0.05 = 5.95g

4 0

3 years ago

What is the balanced chemical equation for the reaction of aqueous sodium hydroxide and sulfuric acid?

Andrews [41]

Answer:

H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).

Explanation:

6 0

3 years ago

October 15, 2018 at 1:49 PM Dioxybenzone is a compound found in sunscreen, and only contains carbon, oxygen, and hydrogen. Analy

-Dominant- [34]

Answer:

Molecular formula for Dioxybenzone is C₁₄H₁₂O₄

Explanation:

Percent composition:

In 100 g of compound → 4.92 g are H

In 100 g of compound → 26.8 g are O

In 100 g of compound → 68.28 g are C

Let's convert the mass to moles by molar mass:

4.92 g / 1 g/mol = 4.92 moles H

26.8 g / 16 g/mol = 1.67 moles O

68.28 g / 12 g/mol = 5.69 moles C

Now we can apply a rule of three:

100 g of compound have 4.92 moles H, 1.67 moles O, 5.69 moles C

244.25 g of compound must have:

(244.25 g . 4.92 m) / 100 g = 12 moles H

(244.25 g . 1.67 m) / 100 g = 4 moles O

(244.25 g . 5.69 m) / 100 g = 14 moles of C

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3 years ago

Predict where the largest jump between successive ionization energies occurs for Rb.

Irina18 [472]

Answer: confused

Explanation:

8 0

3 years ago