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UNO [17]
2 years ago
12

What is the noble gas electron configuration of bismuth (Bİ)?

Chemistry
2 answers:
iVinArrow [24]2 years ago
8 0

Answer: [Xe] 6s^2 6p^3

Explanation: The noble gases are on the last column of the periodic table and Xenon (Xe) is the noble gas before Bismuth (Bi). Then you go down to the next row which is 6s^2 and 6p^3.

krek1111 [17]2 years ago
4 0

Answer:

The correct answer is {Xe] 4f14 5d10 6s2 6p3

Explanation:

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5 0
3 years ago
Why is amniocentesis a more widely used test than cvs?
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
4 0
3 years ago
Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}

Given:

\left[I_2_{Equilibrium} \right] = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0
3 years ago
Movement of electrons about a central nucleus is a concept by whom?
Alenkasestr [34]
The answer is bohr hope this helps :)
5 0
3 years ago
Read 2 more answers
How many moles (of molecules or formula units) are in each sample?
Alexus [3.1K]

The number of moles in each sample will be 0.391 moles, 30.7 moles, 0.456 moles, and 1350 moles

<h3>What is the number of moles?</h3>

The number of moles of a substance is the ratio of the mass of the substance to the molar mass.

In other words; mole = mass/molar mass.

Thus:

  • moles of 18.0 g NO_2 = 18.0/46

                                   = 0.391 moles

  • moles of 1.35 kg CO_2 = 1350/44

                                         = 30.7 moles

  • moles of 46.1 g KNO_3 = 46.1/101.1

                                          = 0.456 moles

  • moles of 191.8 kg Na_2SO_4 = 191800/142

                                                 = 1350 moles

More on the number of moles of substances can be found here: brainly.com/question/1445383

#SPJ1

5 0
2 years ago
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