Question

Mass in grams of 6.023×1023 atom of Ca​

Answer 1

Answer:

$\boxed {\boxed {\sf 40.08 \ grams}}$

Explanation:

First, find the molar mass of calcium (Ca). This can be found on the Periodic Table.

• 40.08 g/mol

Next, find the number of moles.

Avogadro's Number tells us the number of atoms in one mole.

• It is 6.023*10²³

Therefore, there are 6.023*10²³ atoms in 1 mole.

We have 6.023*10²³ atoms of calcium, so it must also be 1 mole of calcium.

Finally, find the mass. Set up a proportion using the molar mass of calcium.

$1 \ mol \ Ca * \frac{40.09 \ g}{1 \ mol \ Ca}$

Multiply. The moles (mol Ca) will cancel.

$1 * 40.08 \ g$

$40.08 \ g$

There are 40.08 grams in 6.023*10²³ atoms of calcium.