Calculate the mass in grams of 8.35 × 1022 molecules of CBr4.

Chemistry

1 answer:

antiseptic1488 [7]4 years ago

4 0

Answer: 45.983 g CBr₄

Explanation:

To convert from moles to grams, you know that we will need molar mass and Avogadro's number.

Avogadro's number: 6.022×10²³ molecules/mol

Molar mass: 331.627 grams/mol

Now that we have what we need, you can use these to solve for grams. $8.35*10^2^2molecules CBr_{4} *\frac{1mol}{6.022*10^2^3molecules} *\frac{331.627 g}{1 mol} =45.983 g$

Our final answer is 45.983 g CBr₄.

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