Answer:
y=2/3x-2
Step-by-step explanation:
All of the given options are in slope intercept form.
Slope intercept form is y=mx+b
This is where m is the slope fo the line and b is the y intercept
That said, we can simply plug the given values into the form.
y=(2/3)x+(-2)
Simplify
y=2/3x-2
Question 1.). Solve:
2 (x - 1 / 2) = 3 (5 - 2x)
Simplify both sides of equation:
2( x - 1 / 2 ) = 3(5 - 2x )
(2) (x) + (2) ( -1 / 2 ) = (3) (5) + (3) ( -2x )
Distribute:
2x + - 1 = 15 + -6x
2x - 1 = -6x + 15
Add 6x to both sides:
2x - 1 + 6x = -6x + 15 + 6x
8x - 1 = 15
Add 1 to both sides:
8x - 1 + 1 = 15 + 1
8x = 16
Divide both sides by 8:
8x / 8 = 16 / 8
Answer: 2 (x - 1 / 2) = 3 (5 - 2x) ==========> x = 2
Question 2.).
M =======> Amount Malik need
Solution: =========> m ≥ 5
Inequality ========> 8 + 7 + 10 + m ≥ 30
25 + m ≥ 30
Interpretation ==========> Malik needs at least, $5 .00 to get to, $30.00 or more.
Is the solution reasonable ===========> YES
Hope that helps!!!!! : )
Let length of rectangle=x and width be y
.`. area=x*y
now new length=x+12x/10=22x/10
width=y-y/5=4y/5
now .....
new area=new length-new width=22x/10*4y/5
new area=88xy/50
Answer:
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Step-by-step explanation:
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Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
Find out more on combined area at brainly.com/question/12966430
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