<u>Answer:</u> The percentage yield of
is 90.26%.
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
Given mass of
= 80 g
Molar mass of
= 100 g/mol
Plugging values in equation 1:

For the given chemical equation:

By the stoichiometry of the reaction:
If 1 mole of
produces 1 mole of 
So, 0.8 moles of
will produce =
of 
Molar mass of
= 44 g/mol
Plugging values in equation 1:

The percent yield of a reaction is calculated by using an equation:
......(2)
Given values:
Actual value of
= 35.2 g
Theoretical value of
= 39 g
Plugging values in equation 2:

Hence, the percentage yield of
is 90.26%.
<u>Answer:</u> The average atomic mass of copper is 63.55 amu.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
- <u>For
isotope:</u>
Mass of
isotope = 62.94 amu
Percentage abundance of
= 69.17 %
Fractional abundance of
isotope = 0.6917
- <u>For
isotope:</u>
Mass of
isotope = 64.93 amu
Percentage abundance of
= 30.83 %
Fractional abundance of
isotope = 0.3083
Putting values in equation 1, we get:
![\text{Average atomic mass of Copper}=[(62.94\times 0.6917)+(64.93\times 0.3083)]\\\\\text{Average atomic mass of copper}=63.55amu](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20Copper%7D%3D%5B%2862.94%5Ctimes%200.6917%29%2B%2864.93%5Ctimes%200.3083%29%5D%5C%5C%5C%5C%5Ctext%7BAverage%20atomic%20mass%20of%20copper%7D%3D63.55amu)
Hence, the average atomic mass of copper is 63.55 amu.
Adenosine triphosphate is the correct answer
Answer:
The initial temperature is 499 K
Explanation:
Step 1: Data given
initial volume = 12 cm3 = 12 mL
Final volume = 7 cm3 = 7mL
The final temperature = 18 °C = 291 K
Step 2: Calculate the initial temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 0.012 L
⇒with T1 = the initial volume = ?
⇒with V2 = the final volume 0.007 L
⇒with T2 = The final temperature = 291 K
0.012 / T1 = 0.007 / 291
0.012/T1 = 2.4055*10^-5
T1 = 0.012/2.4055*10^-5
T1 = 499 K
The initial temperature is 499 K
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