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stepladder [879]
3 years ago
13

True or False: if chemicals behave in a similar way they are grouped together on the periodic table​

Chemistry
1 answer:
sasho [114]3 years ago
6 0

Answer:

Explanation: it is true

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When heat is applied to 80 grams of CaCO3, it yields 39 grams of CO2. Determine
galben [10]

<u>Answer:</u> The percentage yield of CO_2 is 90.26%.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of CaCO_3 = 80 g

Molar mass of CaCO_3 = 100 g/mol

Plugging values in equation 1:

\text{Moles of }CaCO_3=\frac{80g}{100g/mol}=0.8 mol

For the given chemical equation:

CaCO_3\rightarow CaO+CO_2

By the stoichiometry of the reaction:

If 1 mole of CaCO_3 produces 1 mole of CO_2

So, 0.8 moles of CaCO_3 will produce = \frac{1}{1}\times 0.8=0.8mol of CO_2

Molar mass of CO_2 = 44 g/mol

Plugging values in equation 1:

\text{Mass of }CO_2=(0.8mol\times 44g/mol)=35.2g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(2)

Given values:

Actual value of CO_2 = 35.2 g

Theoretical value of H_2CO_3 = 39 g

Plugging values in equation 2:

\% \text{yield of }CO_2=\frac{35.2g}{39g}\times 100\\\\\% \text{yield of }CO_2=90.26\%

Hence, the percentage yield of CO_2 is 90.26%.

8 0
3 years ago
Enter your answer in the provided box. The atomic masses of 63Cu (69.17 percent) and 65Cu (30.83 percent) are 62.94 and 64.93 am
dybincka [34]

<u>Answer:</u> The average atomic mass of copper is 63.55 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

  • <u>For _{29}^{63}\textrm{Cu} isotope:</u>

Mass of _{29}^{63}\textrm{Cu} isotope = 62.94 amu

Percentage abundance of _{29}^{63}\textrm{Cu} = 69.17 %

Fractional abundance of _{29}^{63}\textrm{Cu} isotope = 0.6917

  • <u>For _{29}^{65}\textrm{Cu} isotope:</u>

Mass of _{29}^{65}\textrm{Cu} isotope = 64.93 amu

Percentage abundance of _{29}^{65}\textrm{Cu} = 30.83 %

Fractional abundance of _{29}^{65}\textrm{Cu} isotope = 0.3083

Putting values in equation 1, we get:

\text{Average atomic mass of Copper}=[(62.94\times 0.6917)+(64.93\times 0.3083)]\\\\\text{Average atomic mass of copper}=63.55amu

Hence, the average atomic mass of copper is 63.55 amu.

4 0
3 years ago
Where is enery convert to a more usabled form in a process called cellular respiration?
kari74 [83]
Adenosine triphosphate is the correct answer
7 0
4 years ago
When the temperature of a gas changes, it's volume decreases from 12 cm3 to 7 cm3 if the final temperature is measured to be 18°
ElenaW [278]

Answer:

The initial temperature is 499 K

Explanation:

Step 1: Data given

initial volume = 12 cm3 = 12 mL

Final volume = 7 cm3 = 7mL

The final temperature = 18 °C = 291 K

Step 2: Calculate the initial temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 0.012 L

⇒with T1 = the initial volume = ?

⇒with V2 = the final volume 0.007 L

⇒with T2 = The final temperature = 291 K

0.012 / T1 = 0.007 / 291

0.012/T1 = 2.4055*10^-5

T1 = 0.012/2.4055*10^-5

T1 = 499 K

The initial temperature is 499 K

8 0
3 years ago
Help pls What have you taken away from the work of Stephen Hawking?
Ivahew [28]

When Stephen Hawking was diagnosed with ALS at age 21, he knew he had little time left. But he also knew he wanted to do so much more first. With these circumstances, he learned the importance of carpe diem .

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