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ElenaW [278]
3 years ago
14

Which of the following is ONE of the signs of a chemical change

Chemistry
2 answers:
Vlada [557]3 years ago
7 0
Which ONE please can you show the signs
pickupchik [31]3 years ago
6 0

Answer:

um i one of what?

Explanation:

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The element whose neutral isolated atoms in the ground state have three half filled orbital is
jolli1 [7]
One would be phosporous whose configuration is 1s2 2s2 2p6 3s2 3p3
5 0
3 years ago
The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, w
Natali [406]

 The  partial  pressure of  gas C  is 0.902  atm


  calculation

partial pressure of gas c  =[( percent by volume of  gas   C /  total  percent)   x total pressure]


percent  by  volume of gas C= 22%

Total   percent  = 36% +42%  + 22%  = 100 %

Total  pressure  =  4.1 atm


partial  pressure  of gas C  is therefore =  22/100 x 4.1 atm = 0.902  atm

3 0
3 years ago
Read 2 more answers
Hello<br>Thank you for not answering my question
julsineya [31]
**Visible confusion** no problem
4 0
3 years ago
What information does the third quantum number of an electron give? A. The direction the electron in spinning B. The energy leve
Juli2301 [7.4K]

The information that the third quantum number of an electron gives is the direction the electron in spinning. That is option A.

<h3>What are quantum numbers?</h3>

Quantum number are those numbers that are used to specify the properties of the atomic orbitals and the electrons in those orbitals.

The types of quantum numbers include the following:

  • principal,

  • azimuthal,

  • magnetic, and spin.

The third quantum number is shows the direction of the electron while spinning through specifying its angular momentum.

Learn more about orbitals here:

brainly.com/question/14361631

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4 0
2 years ago
How many grams of ca are needed to react completely with 2.20 L of a 4.50 m hcl solution
Dmitry_Shevchenko [17]
Ca + 2HCl = CaCl₂ + H₂

c=4.50 mol/l
v=2.20 l

n(HCl)=cv

m(Ca)/M(Ca)=n(HCl)/2

m(Ca)=M(Ca)cv/2

m(Ca)=40g/mol·4.50mol/l·2.20l/2=198 g

198 grams of Ca are needed

5 0
3 years ago
Read 2 more answers
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