Which of the following is ONE of the signs of a chemical change
2 answers:
You might be interested in
Answer:
21.5 g.
Explanation:
Hello!
In this case, since the reaction between the given compounds is:
We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:
Now, the moles of Li3P consumed by 15 g of Al2O3:
Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:
Therefore, the total mass of products is:
Which is not the same to the reactants (53 g) because there is an excess of Li₃P.
Best Regards!
The mass of water produced by the reaction of the 23 g of is 13.8 g.
The given chemical reaction;
In the given compound above, we can deduce the following;
- molecular mass of
= 28 + (2 x 16) = 60 g
- molecular mass of
= 2(18) = 36 g
60 g of --------- 36 g of water
23 g of ------------- ? of water
Thus, the mass of water produced by the reaction of the 23 g of is 13.8 g.
- <em>"Your question is not complete, it seems to be missing the following information";</em>
In the reaction of the given compound, , what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?
Learn more here:brainly.com/question/13644576
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting the values in the equation
T = 4342 K
initial temperature was 4342 K
P/T = k
where P - pressure , T - temperature and k - constant
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting the values in the equation
T = 4342 K
initial temperature was 4342 K