Answer:
Volume of acid, Va=250mL; Volume of quinine,Vb=20mL; Molarity of acid, Ma=0.05M.
Molar mass of acid= H2+S+O4= 2+32+(16X4)= 2+32+64=98g
Concentration of acid, Ca= Molar mass of acid/ Ma =98/0.05=1960g/mol
Explanation: To calculate concentration of quinine, Cb is as follow
Va*Ca=Vb*Cb
∴ Cb=Va*Ca/Vb =250*1960/20 =24500g/mol
Answer: Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.
Explanation: Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.
Answer:
87.9%
Explanation:
Balanced Chemical Equation:
HCl + NaOH = NaCl + H2O
We are Given:
Mass of H2O = 9.17 g
Mass of HCl = 21.1 g
Mass of NaOH = 43.6 g
First, calculate the moles of both HCl and NaOH:
Moles of HCl: 21.1 g of HCl x 1 mole of HCl/36.46 g of HCl = 0.579 moles
Moles of NaOH: 43.6 g of NaOH x 1 mole of NaOH/40.00 g of NaOH = 1.09 moles
Here you calculate the mole of H2O from the moles of both HCl and NaOH using the balanced chemical equation:
Moles of H2O from the moles of HCl: 0.579 moles of HCl x 1 mole of H2O/1 mole of HCl = 0.579 moles
Moles of H2O from the moles of NaOH: 1.09 moles of HCl x 1 mole of H2O/1 mole of NaOH = 1.09 moles
From the calculations above, we can see that the limiting reagent is HCl because it produced the lower amount of moles of H2O. Therefore, we use 0.579 moles and NOT 1.09 moles to calculate the mass of H2O:
Mass of H2O: 0.579 moles of H2O x 18.02 g of H2O/1 mole of H2O = 10.43 g
% yield of H2O = actual yield/theoretical yield x 100= 9.17 g/10.43 g x 100 = 87.9%
It loses an H+.
The bronsted lowry definition for an acid is that an acid is a H+ donor, or giver. So, during an acid based reaction, an acid would lose a H+.
Lose an H+.
Answer:
Al (s) + AgClO3 (aq) will result in a chemical reaction.
Al(s) + 3AgClO₃(aq) -----> Al(ClO₃)₃(aq) + 3Ag(s)
Cd(s) + CuNO3(aq) will also result in a chemical reaction.
Cd(s) + 2CuNO₃ -----> Cd(NO₃)₂ + 2Cu
Explanation:
For chemical reactions, metals lower on the activity series cannot normally displace ions of metals higher than them in the activity series.
Metals at the lower end of the activity series are not easily oxidized.
The activity series is attached to this solution. (Note: Cadmium is not on the attached chart, but Cadmium is between Iron (Fe) & Cobalt (Co) on the activity series)
- Pb is way lower Mg in the activity series, hence, it cannot become oxidized by displacing Mg2+ ion in solution.
- Al is way higher than Ag in the activity series. Hence it will easily be oxidized and displace displace Ag from it's solution easily.
- Cadmium will displace Copper in solution too because Cd is higher than Cu on the activity series.
- Platinum cannot displace Cobalt from solution as Pt is lower than Co on the activity series.
