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devlian [24]
3 years ago
5

A baby with an X and a Y chromosome will be a boy •true •false

Chemistry
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

False?

Explanation:

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A population of large predator
dangina [55]

Answer:

they will eat a lot of fish and make other animals go hungry

Explanation:

logic

3 0
3 years ago
Read 2 more answers
Which of the following pairs of elements is most likely to form an ionic compound? a oxygen and fluorine b sodium and aluminum c
irina [24]

An ionic compound consists of a metal AND a non-metal.

<em>Option A:</em>

Oxygen and fluorine are non-metals.

<em>Option B:</em>

Sodium and aluminium are non-metals.

<em>Option C:</em>

Calcium is a metal and chlorine is a non-metal.

<em>Option D:</em>

Nitrogen and sulfur are non-metals.

Thus, the answer is C.

4 0
3 years ago
Explain why the molar ratio is needed to determine the theoretical mass ratios.
choli [55]

Answer:

The overview of the subject is outlined underneath in the summary tab.

Explanation:

  • The molar ratio seems to be essentially a balanced chemical equilibrium coefficient that implies or serves as a conversion factor for the product-related reactants.
  • This ratio just says the reactant proportion which reacts, but not the exact quantity of the reacting product. Consequently, the molar ratio should only be used to provide theoretical instead of just a definite mass ratio.

3 0
3 years ago
When an atom of calcium (Ca) forms an ion by losing two electrons, what is the ion’s type and charge?
posledela

Answer:

cation +2

Explanation:

A cation is a positively charged ion, while an anion is a negatively charged ion. Contrary to how it sounds, when an atom loses electrons, it's charge becomes more positive. Since the calcium atom lost 2 electrons, it is a positive (+2) ion.

5 0
3 years ago
Read 2 more answers
A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, c
natka813 [3]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

  • Ca: 40.078.

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

  • The mass of one mole of CaCO₃ is the same as the molar mass of this compound: \rm 100\; g.
  • The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: \rm 40.078\; g.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}.

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be \rm 30 \% \times 100\; g = 30\; g of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio \displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}:

\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}.

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%.

3 0
3 years ago
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