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Answer:
2.353 × 10⁵ years
Explanation:
Since speed, v = distance/time
time, t = distance/speed
The distance, d = circumference of orbit = 2πr where r = radius of orbit = 8.5 kiloparsecs = 8.5 kiloparsecs × 3.1 × 10¹³ kilometers/parsec = 26.35 × 10¹³ kilometers and velocity of sun, v = 220 km/s
So, the time it takes to complete one orbit, T is
T = 2πr/v
= 2π × 26.35 × 10¹³ km/220 km/s
= 165.562 × 10¹³ km ÷ 220 km/s
= 0.753 × 10¹³ s
= 7.53 × 10¹² s
We now convert T to years
T = 7.53 × 10¹² s ÷ 3.2 × 10⁷ seconds/year
T = 2.353 × 10⁵ years
Answer:
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Explanation:
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Answer:
(a) 1462.38 m/s
(b) 2068.13 m/s
Explanation:
(a)
The Kinetic energy of the atom can be given as:
K.E = (3/2)KT
where,
K = Boltzman's Constant = 1.38 x 10⁻²³ J/k
K.E = Kinetic Energy of atoms = 343 K
T = absolute temperature of atoms
The K.E is also given as:
K.E = (1/2)mv²
Comparing both equations:
(1/2)mv² = (3/2)KT
v² = 3KT/m
v = √[3KT/m]
where,
m = mass of Helium = (4 A.M.U)(1.66 X 10⁻²⁷ kg/ A.M.U) = 6.64 x 10⁻²⁷ kg
v = RMS Speed of Helium Atoms = ?
Therefore,
v = √[(3)(1.38 x 10⁻²³ J/K)(343 K)/(6.64 x 10⁻²⁷ kg)]
<u>v = 1462.38 m/s</u>
(b)
For double temperature:
T = 2 x 343 K = 686 K
all other data remains same:
v = √[(3)(1.38 x 10⁻²³ J/K)(686 K)/(6.64 x 10⁻²⁷ kg)]
<u>v = 2068.13 m/s</u>
