17.3 L.
<h3>Explanation</h3>
The object appears 
lighter in water than in the air. Water has supplied that 170 N of buoyant force.
The size of the buoyant force on an object in water is the same as the weight of water that the object has displaced. The buoyant force on the metal object here is 170 N. The object must have displaced water of the same weight.
.
Mass of water displaced:
.
Volume of water displaced:
The density of water at room temperature is 
. Each kilogram of water will occupy a volume of 1 dm³ (one cubic decimeter), which is the same as 1 L (one liter).
.
Volume of the object:
The object is completely under water. As a result, the volume of the object will be the same as the volume of water displaced. The volume of the object is also 17.3 L.
You just need to replace x with 5 in each function
.5^5 - 11
-5-3
.5 ^-6
-8
64 - 8 = 56 A Celcius
Hope this helps
Answer:
1.) 274.5v
2.) 206.8v
Explanation:
1.) Given that In one part of the lab activities, students connected a 2.50 µF capacitor to a 746 V power source, whilst connected a second 6.80 µF capacitor to a 562 V source.
The potential difference and charge across EACH capacitor will be
V = Voe
Where Vo = initial voltage
e = natural logarithm = 2.718
For the first capacitor 2.50 µF,
V = Vo × 2.718
746 = Vo × 2.718
Vo = 746/2.718
Vo = 274.5v
To calculate the charge, use the below formula.
Q = CV
Q = 2.5 × 10^-6 × 274.5
Q = 6.86 × 10^-4 C
For the second capacitor 6.80 µF
V = Voe
562 = Vo × 2.718
Vo = 562/2.718
Vo = 206.77v
The charge on it will be
Q = CV
Q = 6.8 × 10^-6 × 206.77
Q = 1.41 × 10^-3 C
B.) Using the formula V = Voe again
165 = Vo × 2.718
Vo = 165 /2.718
Vo = 60.71v
Q = C × 60.71
Q = C
I believe that the answer to the question provided above is that <span>the most important process in cooling earth’s surface is the production of oxygen by trees , since it has cooling effect and CO2 is reduced.</span>
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.
