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pychu [463]
3 years ago
12

Consider the double-fluid manometer attached to an air pipe shown. If the specific gravity of one fluid is 14.514.5, determine t

he specific gravity of the other fluid if pressure of air was 81kpa81kpa. Take the atmospheric pressure to be 100 kpa.

Physics
1 answer:
kvv77 [185]3 years ago
5 0

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  value  is  S_g_2  =  3.128

Explanation:

From the question we are told that  

  The specific gravity of the first fluid  is  S_g_1 =  14.5

  The  pressure of air is  P_a  =  81kPa  =  81*10^{3} \  Pa

  The  atmospheric pressure is  P_A  =  100 kPa  =  100 *10^{3}  Pa

Generally the specific gravity of the second  fluid is mathematically represented as

            S_g_2  =  S_g_1  * \frac{h_1}{ h_2 }  +  \frac{P_a  -  P_A}{\rho_w *  g *  h_2 }

Here  \rho_w is the density of water with value \rho_w  =  1000 \  kg/m^3

=>   S_g_2  =  [14.5 *  \frac{0.22}{0.4} ] +  [\frac{81*10^{3}-100*10^{3}}{ 1000 *  9.8 *  0.4} ]

=> S_g_2  =  3.128

   

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